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Homework help needed for displaying ASCII Characters

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Join Date: Oct 2009

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Homework help needed for displaying ASCII Characters

Oct 21st, 2009

Problem: Write a program that uses a loop to display the characters for each ASCII code 32 through 127. Display 16 characters on each line with one space between characters.

I have tried solving this problem several ways. I either get blank screen or numbers 1-16. Can anyone lend a hand please?

This is what I got so far

#include <iostream>
using namespace std;

int main()
{
int num = 0;
char letter;

while (num <= 16)
{
letter = 32;
cout << letter << " " << endl;
num++;
}
return 0;
}

tried:
#include <iostream>
using namespace std;

int main()
{
int num = 0;
char letter;

while (num <= 16)
{
letter = 32;
cout << num << " " << endl;
num++;
}
return 0;
}

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Join Date: Oct 2005

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Reputation: Clinton Portis is an unknown quantity at this point

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Posting Whiz

Oct 21st, 2009

Try this:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
 
char letter = 32;
int counter = 0;
 
while (letter < 128)
{    
     cout << letter << ' ';
 
     counter++;
 
     if(counter == 16)
     {
         cout << endl;
         counter = 0;
     }
 
     letter++;     
}
char letter = 32;
int counter = 0;

while (letter < 128)
{    
     cout << letter << ' ';

     counter++;

     if(counter == 16)
     {
         cout << endl;
         counter = 0;
     }

     letter++;     
}

Last edited by Clinton Portis; Oct 21st, 2009 at 11:43 am.

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-1

Oct 21st, 2009

I tried that and my printout is blank
{
char letter = 32;
int counter = 0;

while (letter < 128)
{
cout << letter << " ";
counter++;
}
if (counter == 16)
{
cout << endl;
counter = 0;
}
letter++;
return 0;
}

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Join Date: Oct 2009

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Oct 23rd, 2009

I tried your advice but I am getting a blank output screen. this is what I put in, possible that I am missing something? Please not that I am a beginner and just started to learn this in August of 09. I may not understand what you post so if you could be kind and give an explanation on your code I would greatly appreciate it so I can better understand why it's done like this or that. I would learn more out of it and not just get an answer to my issue.

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Lerner

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Posting Virtuoso

Oct 23rd, 2009

Notice the different placements of the curly brackets betweenn the code written by Clinton Portis and your code. He checks the value of counter within the while loop to start a new line if needed, you check it outside the while loop.

Try this:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include iostream
using namespace std;
int main()
{
   char letter = 32;
   cout << letter;
   cin.get();
   return 0;
}
#include iostream
using namespace std;
int main()
{
   char letter = 32;
   cout << letter;
   cin.get();
   return 0;
}

If that prints a char to the screen, then the code posted above this post should work ok, too. If not you could try an explicit cast from int to char like this:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include iostream
using namespace std;
int main()
{
   char letter = (char)32;
   cout << letter;
   cin.get();
   return 0;
}
#include iostream
using namespace std;
int main()
{
   char letter = (char)32;
   cout << letter;
   cin.get();
   return 0;
}

though you may want to use the up to date C++ version of casting rather than the older C version I demonstrated above.

Klatu Barada Nikto

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Oct 24th, 2009

Ok I see what I was doing wrong. I followed Portis script and it now displays the characters but it keeps looping, I have to hit Ctrl+C to terminate output screen. I will have to figure out why that happens, thanks for explaining to me why things were done in the syntax, I am a hardware tech and code is a new language for me