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JavaME bluetooth:javax.bluetooth.BluetoothStateException: too mach concurent requests

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Join Date: Feb 2008

Posts: 91

Reputation: Clawsy is an unknown quantity at this point

Solved Threads: 4

Clawsy

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Junior Poster in Training

JavaME bluetooth:javax.bluetooth.BluetoothStateException: too mach concurent requests

34 Days Ago

I'm developing a bluetooth messaging application which sends text messages between devices.
My problem is when I connect more than 2 devices. After sending some data between them (let us say 3 devices) I get this exception:

javax.bluetooth.BluetoothStateException: too mach concurent requests
at com.sun.kvem.jsr082.bluetooth.ServiceSearcher.start(ServiceSearcher.java:67)
at com.sun.kvem.jsr082.bluetooth.DiscoveryAgentImpl.searchServices(DiscoveryAgentImpl.java:226)
at javax.bluetooth.DiscoveryAgent.searchServices(DiscoveryAgent.java:259)
at BSearch.deviceDiscovered(BSearch.java:78)
at com.sun.kvem.jsr082.impl.bluetooth.BTDeviceDiscoverer.run(+268)
requests.

I get it at device inquiry... this means when the application tries to detect other devices.
This is the function that starts the inquiry:

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
 public void startSearching() throws BluetoothStateException{
     System.out.println("before inquiry");
      LocalDevice localD = LocalDevice.getLocalDevice();
      try
      {
      DiscoveryAgent discoveryA = localD.getDiscoveryAgent();
      discoveryA.startInquiry(DiscoveryAgent.GIAC,this);//////
      }catch(BluetoothStateException bse){         
           }
      isSearching = true;
      System.out.println("dupa inquiry -- waiting");
    }
 public void startSearching() throws BluetoothStateException{
     System.out.println("before inquiry");
      LocalDevice localD = LocalDevice.getLocalDevice();
      try
      {
      DiscoveryAgent discoveryA = localD.getDiscoveryAgent();
      discoveryA.startInquiry(DiscoveryAgent.GIAC,this);//////
      }catch(BluetoothStateException bse){         
           }
      isSearching = true;
      System.out.println("dupa inquiry -- waiting");
    }

This is the function that restarts the inquiry after 4 seconds:

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
 public void serviceSearchCompleted(int transID, int respCode) {////////////////////////////////////////
        pendingSearches--;
        if(!isSearching && pendingSearches==0)
            refreshServList();
 
 
         try { Thread.sleep(4000); }
         catch (InterruptedException ie) {}
 
         if (isRunning == true)
                  try {
                      System.out.println("CONTINUAM CU CAUTAREA");
                        startSearching();//////
                       } catch (BluetoothStateException ex) {
                       ex.printStackTrace();
                      }
    }
 public void serviceSearchCompleted(int transID, int respCode) {////////////////////////////////////////
        pendingSearches--;
        if(!isSearching && pendingSearches==0)
            refreshServList();
       

         try { Thread.sleep(4000); }
         catch (InterruptedException ie) {}

         if (isRunning == true)
                  try {
                      System.out.println("CONTINUAM CU CAUTAREA");
                        startSearching();//////
                       } catch (BluetoothStateException ex) {
                       ex.printStackTrace();
                      }
    }

The class implemets a DiscoveryListener and when I call 'startSearching()' the thread is stoped then started again.

My application searches for devices every 4 seconds (in a separate thread) and after that updates a List with the names of available devices in the area.

Please someone help on this exception... at least give me a good hint because I couldn't find the solution anywhere. Thanks.

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Join Date: May 2006

Posts: 1,826

Reputation: ithelp is a name known to all

Solved Threads: 117

ithelp

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Posting Virtuoso

-1

34 Days Ago

Switch of all devices and switch on again.

•

Join Date: Feb 2008

Posts: 91

Reputation: Clawsy is an unknown quantity at this point

Solved Threads: 4

Clawsy

Offline

Junior Poster in Training

34 Days Ago

No I cannot because that means I interrupt all users and when they join again.... the same thing, that exception. Users must stay connected. I use a refresh function for connection which works nice and I didn't got any exception but it's not detecting devices continously, it's only when I click refresh button.

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