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Distinct Vlaues

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Join Date: Oct 2009

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Reputation: kenmeck03 is an unknown quantity at this point

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kenmeck03

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Distinct Vlaues

29 Days Ago

Write a function called NumDistinctDict that takes a single parameter alist that determines the number of distinct values in alist. For example, the list [1,2,4,2,7] contains 3 unique values (namely 1,2,4 and 7).

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Join Date: Aug 2009

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Reputation: Mathhax0r is an unknown quantity at this point

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Mathhax0r

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29 Days Ago

This sounds suspiciously like homework, so I'll just give you a hint.

someList.index(item) returns the index of the item if it's in some list. Otherwise, it'll throw ValueError.

Example:

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listA = [1,2,3,5]
try:
	listA.index(4)
	print "Four is in the list."
except ValueError:
	print "Four isn't in the list."
listA = [1,2,3,5]
try:
	listA.index(4)
	print "Four is in the list."
except ValueError:
	print "Four isn't in the list."

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Join Date: Dec 2006

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Reputation: woooee is a jewel in the rough

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woooee

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29 Days Ago

This is very simple to do.

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print len(set([1,2,4,2,7]))
print len(set([1,2,4,2,7]))

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Join Date: Jul 2009

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Reputation: masterofpuppets is an unknown quantity at this point

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masterofpuppets masterofpuppets is offline

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28 Days Ago

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Originally Posted by woooee

This is very simple to do.
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print len(set([1,2,4,2,7]))
print len(set([1,2,4,2,7]))

that's really useful...

you could also do it in the old fashion way

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 Python Syntax (Toggle Plain Text) 
def NumDistinctDict( l ):
    distinct = []
    for num in l:
        if num not in distinct:
            distinct += [ num ]
    return len( distinct )
def NumDistinctDict( l ):
    distinct = []
    for num in l:
        if num not in distinct:
            distinct += [ num ]
    return len( distinct )