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int reverse(int num)
{
   int rev = 0;
   while(num>0)
   {
       rev = rev*10 + num%10;
       num = num/10;
   }
   return rev;
}

int reverse(int num) { int rev = 0; while(num>0) { rev = rev*10 + num%10; num = num/10; } return rev; }

Originally Posted by dkalita

when u divide an integer by an integer u get the result also an integer.
generally when u do 3/2 it should have been 1.5 but since both are integer values u will get the result as 1 not 1.5.
If u want 1.5 u have to typecast either of the operands to float.

Originally Posted by nirav99

I am not ignoring dkalita's solution..
ya, its right and perfect....
but Mr tojan you just try to use this logic in char string "tojan"...
obiasly it will not work...
dkalita had ignored me to use "strlen()" function and told that his given solution is best ....
so, i mean to say only that dkalita's logic will work for only integer numbers...
and our C compilers are giving use ready mate functions to make better and easy programing then why we can't use this..???
hope you got it.....!!!

Originally Posted by seo2005

Thanks a lot. So, is the below code correct.

1. #include<stdio.h>
2. #include<conio.h>
3. void main()
4. {
5. int x,y,z;
6. scanf("%d",&x);
7. while(x>0)
8. {
9. y=x/10;
10 z=x%10;
11. x=y;
12. printf("%d",z);
13. }
14. printf("%d",x);
15. }

Originally Posted by seo2005

Thanks a lot. So, is the below code correct.

1. #include<stdio.h>
2. #include<conio.h>
3. void main()
4. {
5. int x,y,z;
6. scanf("%d",&x);
7. while(x>0)
8. {
9. y=x/10;
10 z=x%10;
11. x=y;
12. printf("%d",z);
13. }
14. printf("%d",x);
15. }

Originally Posted by seo2005

y=x/10;
10 z=x%10;
11. x=y;
12. printf("%d",z);

in the above code,

y=3/10=0 thats o.k but

what is 3%10 ?

how will z becomes 3 as explained by dkalita