Java

catch without try

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Join Date: Nov 2009

Posts: 6

Reputation: nonshatter is an unknown quantity at this point

Solved Threads: 0

nonshatter nonshatter is offline

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Newbie Poster

catch without try

Nov 5th, 2009

Can anyone shed some light on these errors?

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public void FaultHandler () {
		int faultCount = 0;
	 while ( faultCount < 4 ) {
		  DatagramPacket request =
			  new DatagramPacket(requestArray, requestArray.length, aHost, proxyPort);	
		  aSocket.send(request);	
	 try {
		  aSocket.setSoTimeout(4000);
		  aSocket.receive(reply);
	      }
	 catch ( SocketTimeoutException e ) {
		  faultCount++;
		  continue; 
	      }
	 catch ( IOException e ){}
		 break;
 
	 catch ( IOException e ) {}	  //----it doesn't like this line!
	      if ( faultCount >= 3 )
	      System.exit(0);
	      }
	}
public void FaultHandler () {
		int faultCount = 0;
	 while ( faultCount < 4 ) {
		  DatagramPacket request =
			  new DatagramPacket(requestArray, requestArray.length, aHost, proxyPort);	
		  aSocket.send(request);	
	 try {
		  aSocket.setSoTimeout(4000);
		  aSocket.receive(reply);
	      }
	 catch ( SocketTimeoutException e ) {
		  faultCount++;
		  continue; 
	      }
	 catch ( IOException e ){}
		 break;
	      
	 catch ( IOException e ) {}	  //----it doesn't like this line!
	      if ( faultCount >= 3 )
	      System.exit(0);
	      }
	}

I keep getting these errors:

'catch' without 'try'
catch ( IOException e ) {}
^
Ex2Client.java:18: ')' expected
catch ( IOException e ) {}
^
Ex2Client.java:18: not a statement
catch ( IOException e ) {}
^
Ex2Client.java:18: ';' expected
catch ( IOException e ) {}

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Join Date: May 2007

Posts: 4,514

Reputation: Ezzaral has a brilliant future

Solved Threads: 523

Ezzaral

Offline

Industrious Poster

Nov 5th, 2009

Walk through and match up your braces.

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Join Date: Apr 2008

Posts: 1,027

Reputation: JamesCherrill is just really nice

Solved Threads: 151

JamesCherrill JamesCherrill is offline

Offline

Veteran Poster

Nov 5th, 2009

The "break" on line 16 is outside any catch, so it terminates the list of catches associated with the previous try. So the catch on line 18 hasn't got a try to match to.

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Join Date: Sep 2009

Posts: 26

Reputation: Cronless is an unknown quantity at this point

Solved Threads: 2

Cronless

Offline

Light Poster

Nov 5th, 2009

In addition to the "break" comment above, which is dead-on, you also can't catch the same exception twice in a try clause...you're catching IOException a second time after the break.

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