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Difference between *p[5] and (*p)[5]?
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I'm not sure about the difference between *p[5] and (*p)[5]?
Please help me clarify them?
Thanks a lot!
Please help me clarify them?
Thanks a lot!
0
#2 Nov 6th, 2009
It turns out that this can be done and that
int (*p1d)[5];
is the proper declaration, i.e. p1d here is a pointer to an array of 5 integers just as it was
under the declaration using the Array type. Note that this is different from
int *p1d[5];
which would make p1d the name of an array of 5 pointers to type int.
int (*p1d)[5];
is the proper declaration, i.e. p1d here is a pointer to an array of 5 integers just as it was
under the declaration using the Array type. Note that this is different from
int *p1d[5];
which would make p1d the name of an array of 5 pointers to type int.
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#3 Nov 6th, 2009
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which would make p1d the name of an array of 5 pointers to type int.
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