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variable concat and exec cmd question

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Join Date: Nov 2007

Posts: 227

Reputation: k2k is an unknown quantity at this point

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k2k

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Posting Whiz in Training

variable concat and exec cmd question

18 Days Ago

basically i need to have 2 variables.. concat them and put them into use.

here is what i have done so far:

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#!/usr/bin/perl
 
$stats = ':/var/tmp/RtcTestHarness/currentTransactionStats.txt';
$console = ':/var/tmp/RtcTestHarness/TestHarnessConsole.log';
 
$client_1 = '9.34.120.36';
 
#$com = $client_1.$stats;
#print $com;         the concat here looks fine...
 
system ("scp $client_1.$currentTranStats .");
#!/usr/bin/perl

$stats = ':/var/tmp/RtcTestHarness/currentTransactionStats.txt';
$console = ':/var/tmp/RtcTestHarness/TestHarnessConsole.log';

$client_1 = '9.34.120.36';

#$com = $client_1.$stats;
#print $com;         the concat here looks fine...
 
system ("scp $client_1.$currentTranStats .");

anything wrong? missing the usage of chomp?

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Join Date: Sep 2009

Posts: 40

Reputation: d5e5 is an unknown quantity at this point

Solved Threads: 6

d5e5

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Light Poster

17 Days Ago

I'm on Windows and don't have the scp utility so can't test your code but I notice you use the variable $currentTranStats without having assigned a value to it.

Also note that while a dot between two text variables acts as the concatenation operator, a dot within double quotes is just a dot. For example,

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DB<1> $x = 'hello';
DB<2> $y = 'there';
DB<3> print "$x.$y";
hello.there
DB<1> $x = 'hello';
DB<2> $y = 'there';
DB<3> print "$x.$y";
hello.there

The values of the two text variables are interpolated into the resulting string, but the dot appears as a literal dot.