Nested Switch Statements

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Nested Switch Statements

 
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  #1
Nov 29th, 2009
Essentially what I'm trying do with nested statements is that when I enter the the second switch stament and when I exit the second switch statement it goes back to the first switch statement menu.

Currently the current code exits the entire program after the second switch exits, which of course was not the plan.
C++ Syntax (Toggle Plain Text) 
  1. #include <stdlib.h>
  2. #include <iostream>
  3. #include <string>
  4.  
  5. using namespace std;
  6. int main(int argc, char** argv) {
  7. int ch1,ch2,tmp;
  8. while(1)
  9. {
  10. cout<<endl<<endl;
  11. cout<<" Menu                          "<<endl;
  12. cout<<" ----------------------------- "<<endl;
  13. cout<<" 1. Select Directory "<<endl;
  14. cout<<" 4. Exit "<<endl;
  15. cout<<" Enter your choice : ";
  16. cin>>ch1;
  17. switch(ch1)
  18. {
  19.    case 1 :{
  20.        while(1) {
  21.            cout<<" Directory Selection"<<endl;
  22.             cout<<" 1. Computing Science "<<endl;
  23.             cout<<" Enter your choice : ";
  24.             cin>>ch2;
  25.            switch(ch2){
  26.                case 1 : break;
  27.                case 4:
  28.                     return 0;
  29.                     break;
  30.            }
  31.        }
  32. }
  33.    case 4:
  34.     return 0;
  35.     break;
  36. }
  37. }
  38.  
  39.     return (EXIT_SUCCESS);
  40. }
Last edited by Kennych; Nov 29th, 2009 at 6:39 am.
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  #2
Nov 29th, 2009
I'm sure there are more elegant solutions to this problem, but here's an example I thought of
C++ Syntax (Toggle Plain Text) 
  1. bool exitloop = false;
  2. switch(ch1)
  3. {
  4.    case 1 :{
  5.        while(1) {
  6.            cout<<" Directory Selection"<<endl;
  7.             cout<<" 1. Computing Science "<<endl;
  8.             cout<<" Enter your choice : ";
  9.             cin>>ch2;
  10.            switch(ch2){
  11.                case 1 : break; //out of inner switch
  12.                case 4 :exitloop = true;  break; //out of inner switch
  13.            }
  14.         if(exitloop)
  15. 	   break;  //out of while
  16.        }
  17.  
  18.    break;  //out of outer switch
  19. 	   }
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  #3
Nov 29th, 2009
I need to use both whiles though.
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  #4
Nov 29th, 2009
This doesn't preclude that. In your outer one you exit from while via the return statement. This one, the break will only exit out one layer.
Last edited by jonsca; Nov 29th, 2009 at 7:30 am.
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  #5
Nov 29th, 2009
Update: I have fixed my issue using the help given by the poster who provided the idea. The code is below. Marking solved!

C++ Syntax (Toggle Plain Text) 
  1. int ch1,ch2,tmp;
  2. while(1)
  3. {
  4.     bool exitloop = false;
  5. cout<<endl<<endl;
  6. cout<<" Menu "<<endl;
  7. cout<<" ----------------------------- "<<endl;
  8. cout<<" 1. Select Directory "<<endl;
  9. cout<<" 4. Exit "<<endl;
  10. cout<<" Enter your choice : ";
  11. cin>>ch1;
  12. switch(ch1)
  13. {
  14. case 1 : {
  15. while(1) {
  16. cout<<" Directory Selection"<<endl;
  17. cout<<" 1. Computing Science "<<endl;
  18. cout<<" Enter your choice : ";
  19. cin>>ch2;
  20. switch(ch2){
  21. case 1 :
  22.     break;
  23. case 4:
  24.     exitloop = true;
  25.     break;
  26. }
  27. if (exitloop == true)
  28.     break;
  29. }
  30. break;
  31. }
  32. case 4:
  33. return 0;
  34. break;
  35. }
  36. }
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return exits the whole function

 
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  #6
Nov 30th, 2009
return statement exits the whole function. In this case it is the main function.
I don't see a point in using break statements after 'return' , they just wont be executed.
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  #7
Nov 30th, 2009
You are correct. I think the OP had that in error. What was suggested was return or break not both.
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