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Views: 1132 | Replies: 2
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Join Date: Sep 2004
Posts: 9
Reputation: 
Rep Power: 0
Solved Threads: 0
Newbie Poster
This one isnt working!
But this one Works
Well not woking in the sense the values of variables ($Date_Added[$num],$Sample_Views[$num]) not coming in the first. Whil in second its working!
Help me
function insertpath($num){
echo " <td colspan=\"3\" align=\"left\"> <br>\n";
echo " <b>Date Published</b>:",$Date_Added[$num] ,"<br>\n";
echo " <b>Sample</b>:",$Sample_Views[$num],"</td>\n";
}
insertpath(0);But this one Works
echo " <td colspan=\"3\" align=\"left\"> <br>\n"; echo " <b>Date Published</b>:",$Date_Added[$num] ,"<br>\n"; echo " <b>Sample</b>:",$Sample_Views[$num],"</td>\n";
Well not woking in the sense the values of variables ($Date_Added[$num],$Sample_Views[$num]) not coming in the first. Whil in second its working!
Help me
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Join Date: Jun 2005
Location: Kansas City, Missouri, USA
Posts: 344
Reputation:
Rep Power: 4
Solved Threads: 4
Posting Whiz
There are two things you need to do to troubleshoot this problem. INSIDE your function, at the very top, do this:
First, echo out one of the arrays like this:
[PHP]
echo "<pre>";
print_r($Date_Added);
echo "</pre>";
[/PHP]
Then echo out the value of $num:
[PHP]
echo "<hr />".$num;
[/PHP]
You should see that $num = 0, but that your array does not even exist. You forgot one important line at the top of your function:
[PHP]
global $Date_Added, $Sample_Views;
[/PHP]
First, echo out one of the arrays like this:
[PHP]
echo "<pre>";
print_r($Date_Added);
echo "</pre>";
[/PHP]
Then echo out the value of $num:
[PHP]
echo "<hr />".$num;
[/PHP]
You should see that $num = 0, but that your array does not even exist. You forgot one important line at the top of your function:
[PHP]
global $Date_Added, $Sample_Views;
[/PHP]
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