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hexadecimal.cpp

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hexadecimal.cpp

 
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  #1
Jul 9th, 2005
hi , Please take a moment to read this
i am trying to write hexadecimal.cpp program for my C++ programming class but i dont know how to do it.
the Project says as follows
You have to design and implement a C++ program that reads numbers from a file,converts them into hex numbers and write the hex numbers to output file. your program should have functions for subtask. It has to check if the number is between 0 and 32767. If it is greater than 32767, your Program should convert it to a number between 0 and 32767.
INPUT FILE
50000
-5
32767
138
15

also don'f forget to eliminate leading 0's in the display of the hex numbers.


i dont know how to write algorithm for hex numbers, rest i can take care of.
If sombody can help me with writing codes for hex numbers ,that will be of great help.
thx guys
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Re: hexadecimal.cpp

 
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  #2
Jul 9th, 2005
Hello,

Well, how do you convert decimal numbers to hex?

10 = A
11 = B
12 = C
13 = D
14 = E
15 = F

You should be able to do it out of division, or you can convert it to binary first and then go from binary to hex.

Work out how you would do it by hand, and then code it.

Christian
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Re: hexadecimal.cpp

 
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  #3
Jul 9th, 2005
We only give homework help to those who show effort

Searching the C and C++ Code Snippets might prove useful. So might doing a Google search on std::hex.
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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Re: hexadecimal.cpp

 
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  #4
Jul 10th, 2005
guys i tried this'
#include <iostream>

using namespace std;
int input;
int rem;
char hex1;


int divisor;

int main()
{
cout<<"Enter the number :";
cin>>input ;
rem = 1;
divisor = input;
while (rem!= 0)
{
divisor = divisor / 16;
rem = divisor%16;
cout<<"Remainder is :"<<rem<<endl;
if (rem == 10)
hex1 = 'A';
if (rem == 11)
hex1 = 'B';
if (rem == 12)
hex1 = 'C';
if (rem == 13)
hex1 = 'D';
if (rem == 14)
hex1 = 'E';
if (rem == 15)
hex1 = 'F';

cout<<"divisor is :"<<divisor<<endl;
cout<<"HEX :"<<hex1<<endl;

hexTotal = hexTotal + hex1;
if (rem == 1)
break;
}

return 0;
}


any suggestion?
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Re: hexadecimal.cpp

 
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  #5
Jul 10th, 2005
Suggestion 1: Put your code in code tags.

Why are you breaking when the remainder is 1?

I think you want rem = divisor % 16 to appear before divisor = divisor / 16.

Your while condition should be: while (divisor != 0)

Also, you forgot the cases where your remainder is less than 10, in terms of setting hex1.

Overall, I'd say your algorithm is perplunked, and you need to do some more thinking.
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Re: hexadecimal.cpp

 
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  #6
Jul 10th, 2005
dear friends
say somthing about nanotechnology
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Re: hexadecimal.cpp

 
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  #7
Jul 10th, 2005
desidude: try somthing like this:
C++ Syntax (Toggle Plain Text) 
  1. std::string Hex(int num)
  2. {
  3.     std::string  s1;
  4.     char sign[] = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
  5.     int div,
  6.         base = 16;
  7.  
  8.     while (num >= 1)
  9.     {
  10.         div = num % base;
  11.         num = num / base;
  12.         s1 = sign[div] + s1;
  13.     }
  14.     return s1;
  15. }
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Re: hexadecimal.cpp

 
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  #8
Jul 10th, 2005
A less funny solution :
C++ Syntax (Toggle Plain Text) 
  1. string toHex(long num)
  2. {
  3. 	char tmp[16];
  4. 	sprintf(tmp, "%x", num);
  5. 	return string(tmp);
  6. }
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Re: hexadecimal.cpp

 
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  #9
Jul 10th, 2005
Well for me it seems that he is trying to reinvent the wheel for a school projeckt, and not use standar function.
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Re: hexadecimal.cpp

 
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  #10
Jul 10th, 2005
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Originally Posted by zyruz
C++ Syntax (Toggle Plain Text) 
  1. std::string Hex(int num)
  2. {
  3.     std::string  s1;
  4.     char sign[] = {'0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f'};
  5. ....
You could also write
C++ Syntax (Toggle Plain Text) 
  1.     char sign[] = "0123456789abcdef";
which might be a bit more manageable.
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