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A simple script to execute a command package
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Join Date: Oct 2004
Posts: 57
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Hi folks,
I'm prepared to write a simple script to execute 20+ commands and could not figure out how to make use of "loop" subject to certain conditions.
If without conditions
It will be a long script. Please advise how to apply "loop" to shorter the script executing all command subject to following conditions
1) All commands except cmd3 should have no output. If there is any it needs to confirm either to continue OR to exit the shell
2) cmd3 should have "/mnt/lfs" output. If no output OR empty output the shell should exit, not continue executing further commands
TIA
satimis
I'm prepared to write a simple script to execute 20+ commands and could not figure out how to make use of "loop" subject to certain conditions.
If without conditions
Shell Scripting Syntax (Toggle Plain Text)
#!/bin/bash cmd1="code1" #the exact/full command cmd2="code2" #the exact/full command cmd3="code3" #the exact/full command etc. cmd1 || exit 1 cmd2 || exit 2 cmd3 || exit 3 ... cmdn || exit n echo "Build environment entered!" exit 0
It will be a long script. Please advise how to apply "loop" to shorter the script executing all command subject to following conditions
1) All commands except cmd3 should have no output. If there is any it needs to confirm either to continue OR to exit the shell
2) cmd3 should have "/mnt/lfs" output. If no output OR empty output the shell should exit, not continue executing further commands
TIA
satimis
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