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Join Date: Aug 2005
Posts: 595
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Posting Pro
Plz look at this code
<< moderator edit: added [code][/code] tags >>
does anybody know how can i access main local variable x, from inside the block, without using pointers or references?
#include<iostream.h>
int x=0;
int main()
{
int x=1;
{
int x=2;
cout<<::x;
cout<<x;
}
return 0;
}does anybody know how can i access main local variable x, from inside the block, without using pointers or references?
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Join Date: Aug 2005
Location: Oklahoma
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Posting Shark
You could always just use better variable naming conventions. Using "x" for the name of every variable doesn't help you, and it doesn't help anybody looking at your code.
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Join Date: Aug 2005
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Posting Pro
Well...this was the question asked to me in my viva exam...and i think having same name in different scopes makes the question more tricky
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Join Date: Feb 2005
Location: Ballarat, Australia
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Junior Poster
Your problem contains the ans.
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cout<<::x;
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Join Date: Aug 2005
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Posting Pro
I guess u didn't understood what i was asking.....i am not talking about the global variable ....iam talking about the local variable inside the main....but thanx anyways i was able to solve this problem
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Join Date: Oct 2004
Location: India
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Light Poster
What's the solution? I mean how do you access the variable inside the main from the inner block?
Life is not a journey to the grave with the intention of arriving safely in a pretty and well-preserved body, but rather to skid in broadside, thoroughly used up, totally worn out, and loudly proclaiming --WOW -- " What a ride!!! " -James Fineous McBride
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Join Date: Jul 2005
Location: London
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Junior Poster
you cant. watch.
The basic rule is a name in an inner scope hides the name in all outer scopes unless the scope resolution operator can be used to access it which is not possible with function scope local variables.
int x=0; // global x
int main()
{
int x=1; // main x
{
int x=2; // block x
cout<< x<<endl; // prints block x
cout<< ::x <<endl; // prints global x accessed with :: scope resolution operator
// there is no way to access main x from here
} // block x dies here
cout<< x; // prints main x
cout <<::x; // prints global x
return 0;
} Give your C++ a BOOST
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Join Date: Aug 2005
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Posting Pro
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Originally Posted by Stoned_coder
you cant. watch.
Yes you can
Here is the solution
#include<iostream.h>
int x=0;
int main()
{
int x=1;
{
cout<<x;//access it before declaring variable in this local scope
int x=2;
cout<<::x;
cout<<x
}
return 0;
} 
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