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Join Date: Nov 2004

Posts: 68

Reputation: harshchandra is an unknown quantity at this point

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harshchandra harshchandra is offline

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Junior Poster in Training

Basic Concept

Sep 29th, 2005

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
# include<stdio.h>
void main()
{  int p;
    p = (1,2,2,100,1);
    printf("%d",p);
}
# include<stdio.h>
void main()
{  int p;
    p = (1,2,2,100,1);
    printf("%d",p);
}

I dont know what will be the output . Can anyone please tell me what exactly second line implies ?? :rolleyes:

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Join Date: Aug 2005

Posts: 598

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SpS

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Re: Basic Concept

Sep 29th, 2005

comma ' , ' operator has left to right associativity

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
# include<stdio.h>
void main()
{  int p;
    p = 1,2;
    printf("%d",p);
}
# include<stdio.h>
void main()
{  int p;
    p = 1,2;
    printf("%d",p);
}

In this case output will be 1

But if we apply ( )
then last value is assigned to p and output will be 2

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Join Date: Sep 2005

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keevin

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Re: Basic Concept

Sep 30th, 2005

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Originally Posted by harshchandra

Help with Code Tags

C Syntax (Toggle Plain Text)
# include<stdio.h>
void main()
{  int p;
    p = (1,2,2,100,1);
    printf("%d",p);
}
# include<stdio.h> void main() { int p; p = (1,2,2,100,1); printf("%d",p); }
I dont know what will be the output . Can anyone please tell me what exactly second line implies ?? :rolleyes:

though p should be declare as an array int p[]

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Join Date: Aug 2005

Posts: 15,494

Reputation: Ancient Dragon has a reputation beyond repute

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Ancient Dragon Ancient Dragon is offline

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Still Learning

Re: Basic Concept

Sep 30th, 2005

if p were an array, then the initializer list would have to be in braces, not parentheses, like this

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
	int p[] = {1,2,2,100};
	int p[] = {1,2,2,100};

But the above is entirely different than the code you originally posted.

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Join Date: Sep 2005

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Reputation: Rajendra Bansal is an unknown quantity at this point

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Rajendra Bansal Rajendra Bansal is offline

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Re: Basic Concept

Oct 10th, 2005

># include<stdio.h>
>void main()
>{ int p;
> p = 1,2;
> printf("%d",p);
>}
>In this case output will be 1

what will be the output, if i make a bit of change in the existing code, i mean:::

# include<stdio.h>
void main()
{ int p = 1,2;
printf("%d",p);
}

i got error in this case, i dont know , why its producing error in this case, when it looks similar to the old one??