random number display the same

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Join Date: Aug 2005
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plazmo plazmo is offline Offline
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random number display the same

 
0
  #1
Sep 29th, 2005
im having problems with the following code
it works fine when i have the sleep in
but without the sleep it writes the same number twice
does this have something to do with the way the computer generates the random number? like based on the computers time?
C# Syntax (Toggle Plain Text) 
  1.  
  2.  
  3. using System;
  4. using System.Threading;
  5.  
  6.  
  7. namespace RandomNumber
  8. {
  9.    class RandNum
  10.    {
  11.       [STAThread]
  12.       static void Main(string[] args)
  13.       {
  14.          Console.WriteLine("Random number pairs from 1-6 - type \"q\" to quit");
  15.  
  16.          Console.WriteLine("{0}, {1}", GetRandNum(1,6), GetRandNum(1,6));
  17.          string p = "";
  18.          while(p != "q")
  19.          {
  20.             p = Console.ReadLine();
  21.             if(p == "")
  22.             {
  23.  
  24.                Console.WriteLine("{0}, {1}", GetRandNum(1,6), GetRandNum(1,6));
  25.             }
  26.  
  27.  
  28.       }
  29.       static int GetRandNum(int iStart, int iEnd)
  30.       {
  31.  
  32.  
  33.          Random r = new Random();
  34.  
  35. //         //sleeping helps generate random number
  36.          Thread.Sleep(r.Next(100));
  37.  
  38.          int i = r.Next(iStart, iEnd * iEnd);
  39.          i = i/iEnd + 1;
  40.          return i;
  41.  
  42.       }
  43.  
  44.    }
  45. }
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Re: random number display the same

 
0
  #2
Sep 29th, 2005
Greeting:
That a usual problem with random number, the best way to minimize this to use a seed for the random based on the actual time, something like this:
C# Syntax (Toggle Plain Text) 
  1. DateTime x=DateTime.Now();
  2. float mins=x.Minute;
  3. float secs=x.Second;
  4. float hour=x.Hour;
  5. Random r=new Random((secs*mins)+hour);

This way unless you run your program at the exact same hour every time, you`ll have different random numbers each time.
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Re: random number display the same

 
0
  #3
Sep 29th, 2005
i fixed it, it was because i was creating 2 new randoms at the same time which gave them both the same seed.
so i just made outside the method



C# Syntax (Toggle Plain Text) 
  1. using System;
  2. using System.Threading;
  3.  
  4.  
  5. namespace RandomNumber
  6. {
  7. 	class RandNum
  8. 	{
  9. 		private static Random rNum = new Random();
  10. 		[STAThread]
  11. 		static void Main(string[] args)
  12. 		{
  13. 			int iMin = 1;
  14. 			int iMax = 6;
  15. 			Console.WriteLine("Random number pairs from 1-6 - type \"q\" to quit");
  16. 			string p = "";
  17. 			while(p != "q")
  18. 			{
  19. 				if(p == "")
  20. 				{
  21. 					Console.WriteLine("{0}, {1}", rNum.Next(iMin, iMax), rNum.Next(iMin, iMax));
  22. 				}
  23.  
  24. 				p = Console.ReadLine();
  25. 			}
  26.  
  27. 		}
  28.  
  29. 	}
  30. }
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h2c357 h2c357 is offline Offline
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Re: random number display the same

 
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  #4
Nov 5th, 2008
Standard way to create random numbers is to create a Random object in class wide or global scope and use object's Next() method to get next random number.

This article explains this in detail.
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Re: random number display the same

 
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  #5
Nov 5th, 2008
way to dredge up a 3 yr old post.
Did I just hear "You gotta help us, Doc. We've tried nothin' and we're all out of ideas" ? Is this you? Dont let this be you! I will put in as much effort as you seem to.
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