As much help as he's given you, you should be able to FULLY understand. I'm sorry, but you're just interested in having the program written for you.

Hi riabear123,

The "simple version" is the game I described upthread, where you and I are drawing numbers out of a hat, with you winning pennies every time you get a match. I really wouldn't worry about the logic behind the payoff system until you have completed this simpler problem.

However, in the interest of completeness, let me give you my take on what the assignment specification is asking:

So, you have six numbers and the Random object is used to create six random numbers. The rules are:

1) Look at the first five of your own numbers. Count how many of those five numbers match against any of the six random numbers. Create a variable called x which is equal to this count.

2) Look at the last of your numbers. Does it match the sixth random number? Create a variable called y which is 1 if there is a match and 0 if there is not.

Now, x and y can be used to figure out your payoff. Go to the line in that table above which starts with "x/y." That line has your payoff.

Let's do an example to see how this works. Suppose that our numbers are 4, 8, 15, 16, 23, and 42. Suppose that the current lottery (random) numbers are 8, 1, 13, 2, 34, and 21. In this case, x will be 1 (because only one of the first five lucky numbers, 8, appears in both lists). And since the last numbers don't match, y will be 0. So we go to line 1/0 and see that our payoff is $1 - not much. Now, suppose that we keep the same lucky numbers and get lottery (random) numbers of 22, 15, 41, 8, 16, and 42. In this case, x will be 3 (because three of the first five lucky numbers, 15, 8, and 16, appear in both lists). And since the last numbers match, y will be 1. So we go to line 3/1 and see that our payoff is a whopping $100!

Is this clear? It's not that you're comparing the 2nd lucky number to the 2nd random number - you're comparing to all the random numbers, and you're supposed to do this for each of the first five lucky numbers.

I hope this exchange has helped. Truthfully, I would like to help you more, but I have a fair amount of work to do, myself. Try to code the simple version of the program - you'll get different amounts of pennies each time, but on average (given 5 strips of paper and 1,000,000 tries) you should get about 200,000 of them per execution of the program.

Thank You

I attachted my program so far to this message. My questions are how do I make the y's and X that equal one to add up so I can figure out my winnings

import java.util.Random;
class Lotto
{
public static void main (String[] args)
{
Random r = new Random();
int mynums[] = {6, 11, 15, 36, 37, 40};
int x=0;
int y=0;
int lotto[]= {r.nextInt(49)+1, r.nextInt(49)+1, r.nextInt(49)+1, r.nextInt(49)+1, r.nextInt(49)+1, r.nextInt(42)+1};

System.out.println("I have spent $1,000,000 on lottery tickets ");

{
if (y==1)
{
++y;
}
else
{
if(y==0)
{
y=y+0;
}
}
{





if (lotto[0]==mynums[1])
{
y=1;
}
else
{
if(lotto[0]!=mynums[1])
{
y=0;
}
}
if (lotto[0]==mynums[2])
{
y=1;
}
else
{
if(lotto[0]!=mynums[2])
{
y=0;
}
}
if (lotto[0]==mynums[3])
{
y=1;
}
else
{
if(lotto[0]!=mynums[3])
{
y=0;
}
}
if (lotto[0]==mynums[4])
{
y=1;
}
else
{
if(lotto[0]!=mynums[4])
{
y=0;
}
}

if (lotto[1]==mynums[0])
{
y=1;
}
else
{
if(lotto[1]!=mynums[0])
{
y=0;
}
}
if (lotto[1]==mynums[1])
{
y=1;
}
else
{
if(lotto[1]!=mynums[1])
{
y=0;
}
}
if (lotto[1]==mynums[2])
{
y=1;
}
else
{
if(lotto[1]!=mynums[2])
{
y=0;
}
}
if (lotto[1]==mynums[3])
{
y=1;
}
else
{
if(lotto[1]!=mynums[3])
{
y=0;
}
}
if (lotto[1]==mynums[4])
{
y=1;
}
else
{
if(lotto[1]!=mynums[4])
{
y=0;
}
}
if (lotto[2]==mynums[0])
{
y=1;
}
else
{
if(lotto[2]!=mynums[0])
{
y=0;
}
}
if (lotto[2]==mynums[1])
{
y=1;
}
else
{
if(lotto[2]!=mynums[1])
{
y=0;
}
}
if (lotto[2]==mynums[2])
{
y=1;
}
else
{
if(lotto[2]!=mynums[2])
{
y=0;
}
}
if (lotto[2]==mynums[3])
{
y=1;
}
else
{
if(lotto[3]!=mynums[3])
{
y=0;
}
}
if (lotto[3]==mynums[4])
{
y=1;
}
else
{
if(lotto[3]!=mynums[4])
{
y=0;
}
}
if (lotto[4]==mynums[0])
{
y=1;
}
else
{
if(lotto[4]!=mynums[0])
{
y=0;
}
}
if (lotto[4]==mynums[1])
{
y=1;
}
else
{
if(lotto[4]!=mynums[1])
{
y=0;
}
}
if (lotto[4]==mynums[2])
{
y=1;
}
else
{
if(lotto[4]!=mynums[2])
{
y=0;
}
}
if (lotto[4]==mynums[3])
{
y=1;
}
else
{
if(lotto[4]!=mynums[3])
{
y=0;
}
}
if (lotto[4]==mynums[4])
{
y=1;
}
else
{
if(lotto[4]!=mynums[4])
{
y=0;
}
}

}
if (lotto[5]==mynums[5])
{
x=1;
}
else
{
if(lotto[5]!=mynums[5])
{
x=0;

}
}
}
}
}



But you can see it better by just looking at the attachment

I have the program done now and i know its supposed to print out correctly but I have a small error somewhere that makes it not function. Can someone please check this attatchment?