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Counting occurences in C

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Join Date: Oct 2005

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Counting occurences in C

Oct 15th, 2005

Hi all.
I need some help counting specific numbers in C. The programme should accept two sets of numbers. It should then count how many of the second number is in the first set.

For example:
First input = 23387
Second input = 3
Ouput = "Number 3 appears twice in 23387."

Can someone help me out with the coding ? I'd really appreciate any help.

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Re: Counting occurences in C

Oct 15th, 2005

The easiest way is to input both as strings, not integers, then simply iterator through the string. Attempting to use integers makes that a lot more difficult.

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stabule

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Re: Counting occurences in C

Oct 15th, 2005

Mind giving me a headstart ?

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Re: Counting occurences in C

Oct 15th, 2005

Here is one way to do it. There are probably several other ways too.

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
std::string n = "1233321";
char s = '3';
int count = 0;
for(int i = 0; i < n.length(); i++)
  if(n[i] == s)
    count++;
std::string n = "1233321";
char s = '3';
int count = 0;
for(int i = 0; i < n.length(); i++)
  if(n[i] == s)
    count++;