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Scanning an inputted array of words, and separating each word into a new array?

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Scanning an inputted array of words, and separating each word into a new array?

 
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  #1
Nov 29th, 2005
Is this possible? I would like to have a user input a sentence, and then have each word in that sentence be put into its own array.
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #2
Nov 29th, 2005
Yes it is possible.
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #3
Nov 30th, 2005
make use of string class and its functions...it is very easy
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #4
Nov 30th, 2005
Oh, thanks for the information. I will be sure to look at the string class tonight when I get a chance to finish my program. I assume you are talking about the <string.h> class right? If so, I have tried using the strtok function to break each word into a function. After trying this I cannot seem to figure out how to separate each token into a new array. Or is that even needed to do what I need to do? Do I need to use something other than strtok?
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #5
Nov 30th, 2005
I was talking about <string>
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #6
Nov 30th, 2005
Oh, I have never heard of that. I am using C, not C++ if that makes a difference. Do you know about the strtok function that I am speaking of?
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #7
Nov 30th, 2005
Post your attempt. The basics are something like this:
C Syntax (Toggle Plain Text) 
  1.       static const char delim[] = " \n";
  2.       size_t size = 0;
  3.       char word[10][20], *ptr = strtok(sentence, delim);
  4.       while ( ptr != NULL )
  5.       {
  6.          strcpy(word[size], ptr);
  7.          if ( ++size >= sizeof word / sizeof *word )
  8.          {
  9.             break;
  10.          }
  11.          ptr = strtok(NULL, delim);
  12.       }
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #8
Nov 30th, 2005
Ok, this is my program. I included the entire thing, because when I went to add the part in the main() function about choosing which game to play, it gives an error when I run it. Something is wrong and I have no clue what it is. My attempt at the arrays is in the cellPhone function which is not complete.

Also my compiler is giving me an error if i try to shorten the line length of the menu by entering half of it to a new line. Why is it doing this?

C Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. void nameGame();
  5. void pigLatin();
  6. void changeLatin(char [], int);
  7. void cellPhone();
  8. void cellButtons(char [], int);
  9.  
  10. main()
  11. {
  12. 	int input = 0;
  13.  
  14. 	printf("\n\tEnter your choice:\n\t1. Name Game\n\t2. Pig Latin\n\t3. Text Messaging\n\t4. Exit\n");
  15.  
  16. 	scanf("%d", &input);
  17.  
  18. 	while (input != 4)
  19. 	{
  20. 		if (input == 1)
  21. 			nameGame();
  22. 		else if (input == 2)
  23. 			pigLatin();
  24. 		else if (input == 3)
  25. 			cellPhone();
  26. 		else
  27. 			printf("Invalid choice.  Enter a number 1-4.");
  28.  
  29. 		printf("\n\tEnter your choice:\n\t1. Name Game\n\t2. Pig Latin\n\t3. Text Messaging\n\t4. Exit\n");
  30. 		scanf("%d", &input);
  31. 	}
  32.  
  33. 	return 0;
  34.  
  35. }
  36.  
  37. void nameGame()
  38. {
  39. 	char c, *stringVowel, firstName[25];
  40. 	const char *stringVowels = "aeiou";
  41. 	int i = 0;
  42. 	puts("Enter a first name: ");
  43.  
  44. 	while ( ( c = getchar() ) != '\n')
  45. 		firstName [i++] = c;
  46.  
  47. 	firstName[i] = '\0';
  48.  
  49. 	stringVowel = strpbrk(firstName, stringVowels);
  50.  
  51. 	if (firstName[0] == 'B' || firstName[0] == 'b')
  52. 	{
  53. 		printf("\n%s!\n", firstName);
  54. 		printf("%s, %s bo %s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, strstr(firstName, stringVowel),
  55. 		strstr(firstName, stringVowel), strstr(firstName, stringVowel), firstName);
  56. 	}
  57.  
  58. 	else if (firstName[0] == 'F' || firstName[0] == 'f')
  59. 	{
  60. 		printf("\n%s!\n", firstName);
  61. 		printf("%s, %s bo B%s Bonana fanna fo %s\nFee fy mo M%s, %s!", firstName, firstName, strstr(firstName, stringVowel),
  62. 		strstr(firstName, stringVowel), strstr(firstName, stringVowel), firstName);
  63. 	}
  64.  
  65. 	else if (firstName[0] == 'M' || firstName[0] == 'm')
  66. 	{
  67. 		printf("\n%s!\n", firstName);
  68. 		printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo %s, %s!", firstName, firstName, strstr(firstName, stringVowel),
  69. 		strstr(firstName, stringVowel), strstr(firstName, stringVowel), firstName);
  70. 	}
  71.  
  72. 	else if (firstName[0] == 'A' || firstName[0] == 'a')
  73. 	{
  74. 		firstName[0] = 'a';
  75. 		printf("\n%s!\n", firstName);
  76. 		printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, firstName,
  77. 		firstName, firstName, firstName);
  78. 	}
  79.  
  80. 	else if (firstName[0] == 'E' || firstName[0] == 'e')
  81. 	{
  82. 		firstName[0] = 'e';
  83. 		printf("\n%s!\n", firstName);
  84. 		printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, firstName,
  85. 		firstName, firstName, firstName);
  86. 	}
  87.  
  88. 	else if (firstName[0] == 'I' || firstName[0] == 'i')
  89. 	{
  90. 		firstName[0] = 'i';
  91. 		printf("\n%s!\n", firstName);
  92. 		printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, firstName,
  93. 		firstName, firstName, firstName);
  94. 	}
  95.  
  96. 	else if (firstName[0] == 'O' || firstName[0] == 'o')
  97. 	{
  98. 		firstName[0] = 'o';
  99. 		printf("\n%s!\n", firstName);
  100. 		printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, firstName,
  101. 		firstName, firstName, firstName);
  102. 	}
  103.  
  104. 	else if (firstName[0] == 'U' || firstName[0] == 'u')
  105. 	{
  106. 		firstName[0] = 'u';
  107. 		printf("\n%s!\n", firstName);
  108. 		printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, firstName,
  109. 		firstName, firstName, firstName);
  110. 	}
  111.  
  112. 	else
  113. 	{
  114. 	printf("\n%s!\n", firstName);
  115. 	printf("%s, %s bo B%s Bonana fanna fo F%s\nFee fy mo M%s, %s!", firstName, firstName, strstr(firstName, stringVowel),
  116. 	strstr(firstName, stringVowel), strstr(firstName, stringVowel), firstName);
  117. 	}
  118. }
  119.  
  120. void pigLatin()
  121. {
  122. 	char c, d, sentence[200], tempSentence[200], *wordPtr;
  123. 	int i = 0, j = 0;
  124. 	puts("Enter a sentence: ");
  125.  
  126. 	while ( ( c = getchar() ) != '\n')
  127. 		sentence [i++] = c;
  128.  
  129. 	sentence[i] = '\0';
  130.  
  131. 	wordPtr = strtok(sentence, " ");
  132.  
  133. 	i = 0;
  134.  
  135. 	while (wordPtr != NULL)
  136. 	{
  137. 		printf("%s\t", wordPtr);
  138.  
  139. 		while ( ( d = getchar() ) != '\0')
  140. 		tempSentence [i++] = d;
  141.  
  142. 		printf("%s\n", tempSentence);
  143.  
  144. 		wordPtr = strtok(NULL, " ");
  145. 	}
  146. }
  147.  
  148. void changeLatin(char sentence[200], int i)
  149. {
  150.  
  151. }
  152. void cellPhone()
  153. {
  154. 	char c, sentence[200];
  155. 	int i = 0, j = 0;
  156. 	puts("Enter a sentence: ");
  157.  
  158. 	while ( ( c = getchar() ) != '\n')
  159. 		sentence [i++] = c;
  160.  
  161. 	sentence[i] = '\0';
  162.  
  163. 	cellButtons(sentence, i);
  164. }
  165.  
  166. void cellButtons(char sentence[], int i)
  167. {
  168. 	int j = 0;
  169.  
  170. 	for(j = 0; j < i; j++)
  171. 	{
  172. 		if (sentence[j] == 'A')
  173. 			printf("*2");
  174. 		else if (sentence[j] == 'B')
  175. 			printf("*22");
  176. 		else if (sentence[j] == 'C')
  177. 			printf("*222");
  178. 		else if (sentence[j] == 'D')
  179. 			printf("*3");
  180. 		else if (sentence[j] == 'E')
  181. 			printf("*33");
  182. 		else if (sentence[j] == 'F')
  183. 			printf("*333");
  184. 		else if (sentence[j] == 'G')
  185. 			printf("*4");
  186. 		else if (sentence[j] == 'H')
  187. 			printf("*44");
  188. 		else if (sentence[j] == 'I')
  189. 			printf("*444");
  190. 		else if (sentence[j] == 'J')
  191. 			printf("*5");
  192. 		else if (sentence[j] == 'K')
  193. 			printf("*55");
  194. 		else if (sentence[j] == 'L')
  195. 			printf("*555");
  196. 		else if (sentence[j] == 'M')
  197. 			printf("*6");
  198. 		else if (sentence[j] == 'N')
  199. 			printf("*66");
  200. 		else if (sentence[j] == 'O')
  201. 			printf("*666");
  202. 		else if (sentence[j] == 'P')
  203. 			printf("*7");
  204. 		else if (sentence[j] == 'Q')
  205. 			printf("*77");
  206. 		else if (sentence[j] == 'R')
  207. 			printf("*777");
  208. 		else if (sentence[j] == 'S')
  209. 			printf("*7777");
  210. 		else if (sentence[j] == 'T')
  211. 			printf("*8");
  212. 		else if (sentence[j] == 'U')
  213. 			printf("*88");
  214. 		else if (sentence[j] == 'V')
  215. 			printf("*888");
  216. 		else if (sentence[j] == 'W')
  217. 			printf("*9");
  218. 		else if (sentence[j] == 'X')
  219. 			printf("*99");
  220. 		else if (sentence[j] == 'Y')
  221. 			printf("*999");
  222. 		else if (sentence[j] == 'Z')
  223. 			printf("*9999");
  224. 		else if (sentence[j] == 'a')
  225. 			printf("2");
  226. 		else if (sentence[j] == 'b')
  227. 			printf("22");
  228. 		else if (sentence[j] == 'c')
  229. 			printf("222");
  230. 		else if (sentence[j] == 'd')
  231. 			printf("3");
  232. 		else if (sentence[j] == 'e')
  233. 			printf("33");
  234. 		else if (sentence[j] == 'f')
  235. 			printf("333");
  236. 		else if (sentence[j] == 'g')
  237. 			printf("4");
  238. 		else if (sentence[j] == 'h')
  239. 			printf("44");
  240. 		else if (sentence[j] == 'i')
  241. 			printf("444");
  242. 		else if (sentence[j] == 'j')
  243. 			printf("5");
  244. 		else if (sentence[j] == 'k')
  245. 			printf("55");
  246. 		else if (sentence[j] == 'l')
  247. 			printf("555");
  248. 		else if (sentence[j] == 'm')
  249. 			printf("6");
  250. 		else if (sentence[j] == 'n')
  251. 			printf("66");
  252. 		else if (sentence[j] == 'o')
  253. 			printf("666");
  254. 		else if (sentence[j] == 'p')
  255. 			printf("7");
  256. 		else if (sentence[j] == 'q')
  257. 			printf("77");
  258. 		else if (sentence[j] == 'r')
  259. 			printf("777");
  260. 		else if (sentence[j] == 's')
  261. 			printf("7777");
  262. 		else if (sentence[j] == 't')
  263. 			printf("8");
  264. 		else if (sentence[j] == 'u')
  265. 			printf("88");
  266. 		else if (sentence[j] == 'v')
  267. 			printf("888");
  268. 		else if (sentence[j] == 'w')
  269. 			printf("9");
  270. 		else if (sentence[j] == 'x')
  271. 			printf("99");
  272. 		else if (sentence[j] == 'y')
  273. 			printf("999");
  274. 		else if (sentence[j] == 'z')
  275. 			printf("9999");
  276. 		else if (sentence[j] == '1')
  277. 			printf("1111111111111111");
  278. 		else if (sentence[j] == '2')
  279. 			printf("2222");
  280. 		else if (sentence[j] == '3')
  281. 			printf("3333");
  282. 		else if (sentence[j] == '4')
  283. 			printf("4444");
  284. 		else if (sentence[j] == '5')
  285. 			printf("5555");
  286. 		else if (sentence[j] == '6')
  287. 			printf("6666");
  288. 		else if (sentence[j] == '7')
  289. 			printf("77777");
  290. 		else if (sentence[j] == '8')
  291. 			printf("8888");
  292. 		else if (sentence[j] == '9')
  293. 			printf("99999");
  294. 		else if (sentence[j] == '0')
  295. 			printf("11111111111111111");
  296. 		else if (sentence[j] == '.')
  297. 			printf("1");
  298. 		else if (sentence[j] == '?')
  299. 			printf("11");
  300. 		else if (sentence[j] == '!')
  301. 			printf("111");
  302. 		else if (sentence[j] == ',')
  303. 			printf("1111");
  304. 		else if (sentence[j] == '@')
  305. 			printf("11111");
  306. 		else if (sentence[j] == '-')
  307. 			printf("1111111");
  308. 		else
  309. 			printf("#");		
  310. 	}
  311. 	printf("\n");
  312. }
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #9
Nov 30th, 2005
Ok, I ran your code through my program in place of mine for the pigLatin() function and it works, but how do I access each word's array? I need to modify each word.
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Re: Scanning an inputted array of words, and separating each word into a new array?

 
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  #10
Nov 30th, 2005
From my earlier mockup:
#include <stdio.h>
#include <string.h>

int main(void)
{
   char sentence[200];
   puts("enter a sentence:");
   fflush(stdout);
   if ( fgets(sentence, sizeof sentence, stdin) != NULL )
   {
      static const char delim[] = " \n";
      size_t i, size = 0;
      char word[10][20], *ptr = strtok(sentence, delim);
      while ( ptr != NULL )
      {
         strcpy(word[size], ptr);
         if ( ++size >= sizeof word / sizeof *word )
         {
            break;
         }
         ptr = strtok(NULL, delim);
      }
      puts("words are:");
      for ( i = 0; i < size; ++i )
      {
         puts(word[i]); /* access to each word */
      }
   }
   return 0;
}

/* my output
enter a sentence:
The quick brown fox jumps over the lazy dog.
words are:
The
quick
brown
fox
jumps
over
the
lazy
dog.
*/
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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