vector <char*> constArray(10);
char* changingString = "hello";
 
constArray[0] = changingString;
changingString = "hi";
 
printf("constArray[0] = %s\nchangingString = %s", constArray[0], changingString);

	vector <char*> constArray(10);
	char* changingString = "hello";
 
	constArray[0] = new char;
	constArray[0] = changingString;
	changingString = "yadayada";
 
	printf("constArray[0] = %s\nchangingString = %s\n", constArray[0], changingString);

	vector <char*> constArray(10);
	char* changingString = "hello";
 
        delete constArray[0] ; // error, not initated (I can never remember if deleting 0 is an error or not, so I usually dont) 
        // the vector initates all elements with default constructor, however 
        // I dont remember if default constructor for pointers actually does anything since they are built in types (optimization)
        // testing this results in only zero values but that is
        // likely due to using dynamic memory (which mostly is zero before use, since it get cleared when the process is handed it...
        // for stack variables crapp exists in variables after skipping initation... (enough of ranting, stopping now)...
	constArray[0] = new char;
        delete constArray[0] ; // this is ok, we just gave it a pointer to a char
        delete [] constArray[0] ; // error, did not allocate an char string, only a single char
	constArray[0] = changingString;
        delete [] constArray[0] ; // error, not dynamically allocated
	changingString = "yadayada";
allocated

#include <vector>
#include <stdlib.h>
using namespace std;
 
vector <char*> msgs(100);
 
int main(){
	char changingString[200];
	memcpy(changingString, "hello", 6);
	int numMsgs = 0;
 
	msgs[numMsgs] = changingString;
	memcpy(changingString, "hi", 3);
 
	printf("msgs[%d] = %s\nchangingString = %s", numMsgs, msgs[numMsgs], changingString);
 
	return 0;
}

msgs[numMsgs] = new char[ strlen( changingString ) + 1 ]; 
strcpy( msgs[numMsgs], changingString ) ;

std::vector< std::string > msgs(size) ;
...
msgs[numMsgs] = changingString ;