If I have an array $abc=[0,0,0,1,0,2];
how to change it to $abc=[1,2]; (remove all 0), is there php function can handle that? thanks.

There may be more efficient (execution time?) code than above.

here is the one of the simplest example...

$abc=[0,0,0,1,0,2];
$bcd=array();
for($i=0;$i<count($abc);$i++)
{
if($abc[$i]!="0")
{
array_push($bcd,$abc[$i])
}
}

However, code I've said is better (efficiency!) of two

i am not saying the urs is wrong but mine is more simpler and easier to understand in one look..

Im wondering...

Is this any faster?

[PHP]<?php

function removeVal($array, $val) {

$string = implode(',', $array);
$new_string = str_replace($val.',', ',', $string);
$new_array = explode(',', $new_string);

return $new_array;

}

$abc=[0,0,0,1,0,2];
$new_abc = removeVal($abc, 0);

var_dump($new_abc); // should show new array withought 0s

?>[/PHP]

what do you guys think?...

btw: I think the for loop would be faster...
If you just took the count out of the for loop.

[PHP]$abc=[0,0,0,1,0,2];
$bcd=array();
$count = count($abc);
for($i=0;$i<$count;$i++)
{
if($abc[$i]!="0")
{
array_push($bcd,$abc[$i])
}
} [/PHP]

This way the count is only evaluated once during the loop.
Im not sure if its faster than the while loop though.

I've looked at some benchmark tests. And it seems foreach is fastest. If you just make sure you do not copy the array, but supply the original array ie: &$array.

Heres a way of doing this that seems to be the most efficient.
The $new_array also retains its key values.

[PHP]function removeVals($var) {
return ($var != 0);
}

$new_array = array();
$array = array(0,0,0,1,0,2);
$new_array = array_filter($array, "removeVals");[/PHP]