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Problem with precedence in C
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I am having this problem with precedence of operators. Its with the increment and decrement operators.
this evaluates to 6 instead of 7 . Why does this happen. It would be of great help to me.
Thanks,
comwizz
C Syntax (Toggle Plain Text)
Thanks,
comwizz
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Join Date: Aug 2005
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j++
means j == j +1
but ++j means add one before u do the next thing i thinks.
God bless.
means j == j +1
but ++j means add one before u do the next thing i thinks.
God bless.
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Originally Posted by iamthwee
j++ means j == j +1
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Originally Posted by comwizz
I am having this problem with precedence of operators. Its with the increment and decrement operators.
this evaluates to 6 instead of 7 . Why does this happen. It would be of great help to me.C Syntax (Toggle Plain Text)
Thanks,
comwizz
All my posts may be redistributed under the GNU Free Documentation License.
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Originally Posted by Rashakil Fol
It looks like you're expecting the expression (j++)+(++j)+(j++) to be evaluated from left to right. The C standard does not require this. Because you are modifying your variable j more than once in the same expression, the behavior is undefined.
Thanks,
comwizz.
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Originally Posted by comwizz
Even if we evaluate from the right for j=1 the expression will be evaluated like 1 + 3 + 3 and will still turn out to be 7.
(k = j++ + j++) might be treated equally as either k = j + j; j += 2; or k = j; j += 1; k += j; j += 1;You need to separate your expression into multiple statements. For another example: Is
y[i] = ++i; equivalent to y[i] = i; i += 1; or y[i + 1] = i; i += 1;? All my posts may be redistributed under the GNU Free Documentation License.
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