DaniWeb Forum Index > Software Development > C

C RSS

(C) have 2 parse errors (help)

•

Join Date: Dec 2005

Posts: 16

Reputation: zenoen is an unknown quantity at this point

Solved Threads: 1

zenoen

Offline

Newbie Poster

(C) have 2 parse errors (help)

Jan 17th, 2006

here is my problem
main.c:17: error: parse error before '{' token
main.c:27: error: parse error before string constant

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>
 
#define kmll 200
#define Kzll 0
 
int myint,any,go;
int main (int argc, const char * argv[]) {
 
(myint, any, go) = 0 ;
 
// here parse error
do printf(" helo guys plese incert a number") {
 
if any = 0 {  
 
scanf("%c %c",myint,any);   
 
else 
 
printf(" next code"); } 
 
// here parse error
printf(" %d + %d = %d ", myint, any,(any + myint));
 
else printf(" uno");
 
return 0; }
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>

#define kmll 200
#define Kzll 0

int myint,any,go;
int main (int argc, const char * argv[]) {

(myint, any, go) = 0 ;

// here parse error
do printf(" helo guys plese incert a number") {

if any = 0 {  

scanf("%c %c",myint,any);   

else 

printf(" next code"); } 

// here parse error
printf(" %d + %d = %d ", myint, any,(any + myint));

else printf(" uno");

return 0; }

a quick reply to the problem would be helpfull

•

Join Date: Feb 2005

Posts: 466

Reputation: winbatch is on a distinguished road

Solved Threads: 18

winbatch

Offline

Posting Pro in Training

Re: (C) have 2 parse errors (help)

Jan 17th, 2006

need () around if:
if ( any == 0 )

also, you want == not =

•

Join Date: Aug 2005

Posts: 598

Reputation: SpS is on a distinguished road

Solved Threads: 32

SpS

Offline

Posting Pro

Re: (C) have 2 parse errors (help)

Jan 17th, 2006

try concentrating on { } brackets and matching if-else statements

•

Join Date: Dec 2005

Posts: 16

Reputation: zenoen is an unknown quantity at this point

Solved Threads: 1

zenoen

Offline

Newbie Poster

Re: (C) have 2 parse errors (help)

Jan 18th, 2006

still doesent work please help

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>
 
#define kmll 200
#define Kzll 0
 
int myint,any,go;
int main (int argc, const char * argv[]) {
 
(myint, any, go) == 0 ;
 
 
 
// stupid error is some where under here ( parse error befor '{' token ) 
//help it should work but doesent
/*dang it */ do printf(" helo guys plese incert a number "); {
 
 
while any = 0 {  
 
scanf("%c %c",myint,any);   
 
else 
 
printf(" next code"); } 
 
 
// here 2 im in need of help (parse error befor string constant) 
// i don't see the problem help me
printf(" %d + %d == %d ", myint, any,(any + myint)); 
 
 
else printf(" uno"); }
 
return 0; }
#include <stdio.h>
#include <c.h>
#include <math.h>
#include <ctype.h>
#include <time.h>
#include <stdlib.h>
#include <string.h>

#define kmll 200
#define Kzll 0

int myint,any,go;
int main (int argc, const char * argv[]) {

(myint, any, go) == 0 ;



// stupid error is some where under here ( parse error befor '{' token ) 
//help it should work but doesent
/*dang it */ do printf(" helo guys plese incert a number "); {


while any = 0 {  

scanf("%c %c",myint,any);   

else 

printf(" next code"); } 


// here 2 im in need of help (parse error befor string constant) 
// i don't see the problem help me
printf(" %d + %d == %d ", myint, any,(any + myint)); 


else printf(" uno"); }

return 0; }