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homework question on class...multiple choice
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>if you look at my original question, i stated that
Yes, I read it, but thanks for the reminder anyway.
>the base class mem() is not virtual so dPtr -> mem(); will call Base::mem??
Seeing as how this is a variation of what I said:
It seems like you understand. The real type of dPtr is Base because it was declared as a pointer to Base. mem isn't a polymorphic function, and dPtr has no way of knowing that it actually points to an object of Derived. Therefore, Base::mem is used instead of Derived::mem.
Yes, I read it, but thanks for the reminder anyway.
>the base class mem() is not virtual so dPtr -> mem(); will call Base::mem??
Seeing as how this is a variation of what I said:
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Originally Posted by Narue
so dPtr->mem() will call Base::mem since mem isn't virtual.
I'm here to prove you wrong.
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