hi im having problems with a doubly linked list. im trying to initialise three names into the list and print them straight off using the list and pointers but cant figure out how. heres what i have already if it could be modified i would greatly appreciate. also please keep the explanations simple as i have only recently started c++

#include <iostream.h>
#include <ctype.h>
#include <string.h>

void initialise(Name *&, char arr[], Name *&);
void DisplayList(Name *) ;
main()
{
Name * Head, * Tail ;
Name *Head = NULL,
*Tail = NULL;
Name *mvlr=NULL;

char s1[]="name1";
char s2[]="name2";
char s3[]="name3";

initialise(s1, Head, Tail);
initialise(s2, Head, Tail);
initialise(s3, Head, Tail);
DisplayList(Head) ;
}

void initialise(Name * &H, Name * &T)
{ H = T = NULL ;
}

void DisplayList(Name * H)
{ ListEntry *curr = H ;
if(H != NULL) {
do {
cout << curr->Name << endl ;
curr = curr->Next ;
}while(curr != H) ;
}
}

You've only just started C++ and you're trying to implement a doubly linked list? You might want to start out with a singly linked list first... Also, it's hard to see exactly what is supposed to be going on in your code without seeing the definition of Name

These should be
to..
Error here - you can't redefine names. change to
This is OK, but you might be making life difficult for yourself. I recommend you use the C++ std::string instead of C-Style null-terminated char arrays.

There appears to be a load of other errors too, such as: cout << curr->Name << endl ; but it's impossible to tell what's going on without seeing what Name actually is.