im taking a qbasic class and am having a very hard time on this program...here is the question:
Using the ASCII table and the CHR$ function, write a program that prints the following output using a nested for next loop:
A
AB
ABC
ABCD
ABCDE

--------------------------------------------------------------------
heres what I have so far...i keep getting a "type mismatch":

CLS
FOR Outer = 1 TO 5 STEP 1
FOR in = CHR$(65) TO CHR$(70) <------TYPE MISMATCH?????
PRINT in;
NEXT in
PRINT
NEXT Outer

what am i doing wrong? any help on this would be greatly appreciated....thanks

Well you are making it too difficult, the reason is write in front of you. CHR$(65) gives you what value?

...
Look at your ASCII Table if you don't know off hand.....

It is the Character A .

Now, look at your code. For in = CHR$(65) Stop right there!
If CHR$(65) gives a value of A and in is no doubt an integer value this is where you mismatch starts. You care comparing a Character String (albiet one character) to an Integer! So it unfortunately won't work. Can only compare like datatypes.

So some Conversion will be needed and I think you need to check your logic for this code....

Hope this helps.... If not let me know if you need more help!

I sill don't quite get it. Every time I try and switch it up to change values I get another error. I know im close but just cant figure it out. any suggestions?

first of all, you don't need STEP, because the default step value is always 1. Secondly, A FOR statement is looking for an integer. CHR$() returns a character, which is not a number. Leave the CHR$() out of the FOR header. Look at the example below.

Now lets run through the code step by step. First time through, "outer" will equal 1. So the following statement would actually be "FOR in = 1 to 1". "in" will equal 1 as well. Next line "PRINT CHR$(in+64)" This will be the same as "PRINT CHR$(65)" because "in" is 1. Now the loops starts back from the top. This time, "outer" will equal 2. So therefore, the following FOR statement would really mean "FOR in = 1 to 2". So that FOR loop will run through twice. The first time "in" being 1 and the second time "in" being 2. Which would print CHR$(1+64) and CHR$(2+64). And the pattern repeats until "outer" finally equals 5. Hope this helped you a little.

I just had a problem similar to this one. But I ended up making it harder than it really was. It all clicked when I figured out FOR is looking for integers instea of characters. Here's what I did:

CLS

FOR num = 32 TO 255
PRINT CHR$(num)
NEXT num

END

It can't get more simple than that.

The code below should work if Qbasic works at all like BCX:

dim inner, outer

FOR outer = 1 to 5
FOR inner = 1 to outer
PRINT CHR$(inner + 64); ' stay on line
NEXT innner
PRINT ' new line feed
NEXT outer

Well I do appreciate your help, but I took this class back in April and this is no longer useful to me. I got a B+........thanks anyway