Splitting a string?

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Splitting a string?

 
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  #1
Aug 24th, 2006
Hi,
Hope you can help. The following is essentially a small problem of an overall project, i have been trying to work out how to divide an inputted string, into say blocks of 4 characters and then output these separate blocks on the screen. e.g. 1234567891234567 ----> 1234 5678 9123 4567and so on. here's wat i have so far it seem to be working prob.

i think i must cout<<" " ?

thanks,
hay_man

C Syntax (Toggle Plain Text) 
  1. int strLength = str.length()-1; 
  2. int x= 0;
  3. while (x<strLength)
  4. {
  5. int   j=0;
  6.    while (j < 4){
  7.        newString[j] = str[x];
  8.        cout<< newString[j];
  9.       j++;
  10.     }
  11.     x++;
  12. }
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Re: Splitting a string?

 
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Aug 24th, 2006
You don't need double loop. What you need is one foor loop wich will print str[x] and putchar(' '); if its
if (0 == (x % 4) && 0 != x)
Last edited by andor; Aug 24th, 2006 at 10:53 am.
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Re: Splitting a string?

 
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Aug 24th, 2006 
int strLength = str.length()-1; 
int x= 0;
while (x<strLength)
{
int   j=0;
   while (j < 4){
       newString[j] = str[x];
       cout<< newString[j];
      j++;
    }
cout << " ";
    x++;
}


Should work. This is not really splitting the string! It's just outputting the string with spaces in it.

Greetz, Eddy
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Re: Splitting a string?

 
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  #4
Aug 24th, 2006
Wat is considered spliting a string? and also if i want to manipulate each new string, i would need to split the string?
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Re: Splitting a string?

 
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  #5
Aug 24th, 2006
the output from ur suggestion, which i had tried originally is;
1111 2222 3333 4444 5555 6666 7777 8888 i am trying to creat 1234 5678 9123 4567.
thanks again
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Re: Splitting a string?

 
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  #6
Aug 24th, 2006
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Originally Posted by hay_man View Post
Wat is considered spliting a string? and also if i want to manipulate each new string, i would need to split the string?

Splitting a string is if you have one string, and separate it to 2 strings at a set location.

I cannot give you an example on this now because I'm not at home. Just google for string split c++.


Greetz,Eddy
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Re: Splitting a string?

 
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Aug 24th, 2006
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the output from ur suggestion, which i had tried originally is;
1111 2222 3333 4444 5555 6666 7777 8888 i am trying to creat 1234 5678 9123 4567.
thanks again
I can't belive it. How is this possible
C Syntax (Toggle Plain Text) 
  1.  
  2. for (int x=0; x<strLength; x++)
  3.    {
  4.       if (0 == (x % 4) && 0 != x)
  5.          putchar(' ');
  6.       putchar(str[x]);  
  7.    }
Last edited by andor; Aug 24th, 2006 at 11:03 am.
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Re: Splitting a string?

 
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  #8
Aug 24th, 2006
in addition to splitting the char string, i need to convert it into its correspong integer e.g. "12345678" --> 12345678. then SPLIT the string and sum the blocks e.g. 1234 + 5678. I have written the code to convert the string into an integer value. i must actually split the string not just cout a string with blanks. I assume i must create a series of new integers to store each block then its just a matter of creatin some intger, sum, and sum each individual block.
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Re: Splitting a string?

 
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Aug 24th, 2006
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Originally Posted by hay_man View Post
in addition to splitting the char string, i need to convert it into its correspong integer e.g. "12345678" --> 12345678. then SPLIT the string and sum the blocks e.g. 1234 + 5678. I have written the code to convert the string into an integer value. i must actually split the string not just cout a string with blanks. I assume i must create a series of new integers to store each block then its just a matter of creatin some intger, sum, and sum each individual block.
OK but this is not what you said in first post. Let me think
Last edited by andor; Aug 24th, 2006 at 11:24 am. Reason: Added let me think
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Re: Splitting a string?

 
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  #10
Aug 24th, 2006
What about this
C Syntax (Toggle Plain Text) 
  1.    int strLength = str.length()-1; 
  2.    char temp[5] = { 0, 0, 0, 0, 0};
  3.    int sum = 0;
  4.  
  5.    for (int x=0; x<strLength; x++)
  6.    {
  7.       if (0 == (x % 4) && 0 != x)
  8.       {
  9.          putchar(' ');
  10.          sum += atoi(temp);
  11.       }
  12.       temp[x % 4] = str[x];
  13.       putchar(str[x]);  
  14.    }
  15.    putchar('\n');
  16.    if ((strLength % 4) == 0)
  17.       sum += atoi(temp);
  18.    printf("Final sum %d\n", sum);
Bye
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