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grade prediction program

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Join Date: Sep 2006

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hygy486

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grade prediction program

Sep 6th, 2006

here is my code i get an error of call of non function in lines 29, 34, 39 and 44

apprecite help or an alternate code if possible

here is code

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
 int main (void)
{
  char desiredgrade;
  double min_average;
  double currentaverage;
  double weight;
  double score;
  printf("Please enter your desired grade: \n");
  scanf("%c", &desiredgrade);
  printf("Please enter your minimum average required:  \n");
  scanf("%lf", &min_average);
  printf("Please enter your current average in course:  \n");
  scanf("%lf", &currentaverage);
  printf("Please enter how much the final counts as a percentage of the course grade:  \n");
  scanf("%lf", &weight);
  if ( 92<=desiredgrade && desiredgrade>=100)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get A\n",score);
}
  else if (84<=desiredgrade && desiredgrade>=91)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get B\n",score);
}
  else if (76<=desiredgrade && desiredgrade>=83)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get C\n",score);
}
  else if (68<=desiredgrade && desiredgrade>=75)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get D\n",score);
  return 0 ;
}
  return score ;
}
 int main (void)
{
  char desiredgrade;
  double min_average;
  double currentaverage;
  double weight;
  double score;
  printf("Please enter your desired grade: \n");
  scanf("%c", &desiredgrade);
  printf("Please enter your minimum average required:  \n");
  scanf("%lf", &min_average);
  printf("Please enter your current average in course:  \n");
  scanf("%lf", &currentaverage);
  printf("Please enter how much the final counts as a percentage of the course grade:  \n");
  scanf("%lf", &weight);
  if ( 92<=desiredgrade && desiredgrade>=100)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get A\n",score);
}
  else if (84<=desiredgrade && desiredgrade>=91)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get B\n",score);
}
  else if (76<=desiredgrade && desiredgrade>=83)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get C\n",score);
}
  else if (68<=desiredgrade && desiredgrade>=75)
{
  score=(min_average-(100-weight)(currentaverage/100)+(100/weight));
  printf("You need a score of %.2f on the final to get D\n",score);
  return 0 ;
}
  return score ;
}

Last edited by WolfPack; Sep 6th, 2006 at 1:09 pm. Reason: Code Tags

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Join Date: Jun 2005

Posts: 1,496

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WolfPack

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Mentally Challenged Mod.

Re: grade prediction program

Sep 6th, 2006

You need some kind of operator between these brackets. Probably the multiplication operator. (a)(b) doesnt mean a * b like in algebra.

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   score=(min_average-(100-weight)(currentaverage/100)+(100/weight));

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Join Date: Sep 2006

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hygy486

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Re: grade prediction program

Sep 6th, 2006

then that makes my formula wrong then
that is correct formula

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Join Date: Jun 2005

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WolfPack

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Re: grade prediction program

Sep 6th, 2006

If that doesnt correct your problem write me the Correct Formula mathematically. Use +,-,*,/ only. Don't use any implicit operators.

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Join Date: Sep 2006

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hygy486

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Re: grade prediction program

Sep 6th, 2006

Purpose: To determine data requirements.
To read input.
To process and output data.
To document a program.

Program: Write a program that predicts the score needed on a final exam to achieve a desired grade in a course. The program should interact with the user as follows:
Enter Desired grade: B
Enter minimum average required: 79.5
Enter current average in course: 74.6
Enter how much the final counts as a percentage of the course grade: 25

You need a score of 94.20 on the final to get a B.

[79.5 - 75(.746)] * 4

this is waht his example works out to i need the formula

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Join Date: Jun 2005

Posts: 1,496

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WolfPack

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Mentally Challenged Mod.

Re: grade prediction program

Sep 6th, 2006

•

Originally Posted by hygy486

Enter Desired grade: B
Enter minimum average required: 79.5
Enter current average in course: 74.6
Enter how much the final counts as a percentage of the course grade: 25

You need a score of 94.20 on the final to get a B.
[79.5 - 75(.746)] * 4

Here is a much more smaller program that gives you the required output. No check is done for Desired grade checking. You do that.

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <stdio.h>
 
int main (void)
{
  char desiredgrade;
  double min_average;
  double currentaverage;
  double weight;
  double score;
  printf("Please enter your desired grade: \n");
  scanf("%c", &desiredgrade);
  printf("Please enter your minimum average required:  \n");
  scanf("%lf", &min_average);
  printf("Please enter your current average in course:  \n");
  scanf("%lf", &currentaverage);
  printf("Please enter how much the final counts as a percentage of the course grade:  \n");
  scanf("%lf", &weight);
  score=(min_average-((100-weight)*(currentaverage/100)))*(100/weight);
  printf("You need a score of %.2f on the final to get %c\n",score, desiredgrade);
 
  return 0;
}
#include <stdio.h>

int main (void)
{
  char desiredgrade;
  double min_average;
  double currentaverage;
  double weight;
  double score;
  printf("Please enter your desired grade: \n");
  scanf("%c", &desiredgrade);
  printf("Please enter your minimum average required:  \n");
  scanf("%lf", &min_average);
  printf("Please enter your current average in course:  \n");
  scanf("%lf", &currentaverage);
  printf("Please enter how much the final counts as a percentage of the course grade:  \n");
  scanf("%lf", &weight);
  score=(min_average-((100-weight)*(currentaverage/100)))*(100/weight);
  printf("You need a score of %.2f on the final to get %c\n",score, desiredgrade);
  
  return 0;
}

My output

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
Please enter your desired grade:
B
Please enter your minimum average required:
79.5
Please enter your current average in course:
74.6
Please enter how much the final counts as a percentage of the course grade:
25
You need a score of 94.20 on the final to get B
Please enter your desired grade:
B
Please enter your minimum average required:
79.5
Please enter your current average in course:
74.6
Please enter how much the final counts as a percentage of the course grade:
25
You need a score of 94.20 on the final to get B

Last edited by WolfPack; Sep 6th, 2006 at 2:39 pm. Reason: removed "return score;" score is of type double. main returns int.

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Join Date: Jun 2006

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~s.o.s~

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Failure as a human

Re: grade prediction program

Sep 7th, 2006

Yes you better follow the guidelines laid down by Wolfpack to solve your problem but while finalizing your code just replace the [inlinecode] scanf[/code] with either getchar () for gettign a character or fgets ( ) while getting a string.

scanf is a prettly complex function and leaves the input stream dirty with the junk.

Hope it helped, bye.

Last edited by ~s.o.s~; Sep 7th, 2006 at 2:04 pm.

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