Originally Posted by WaltP

Format your code properly with code tags and finish your for statements (3 parameters, not 2) and repost...

Then we have something readable to work with.

Originally Posted by steveincolorado

If I understand right I needed to enclose my code in [] right?

Originally Posted by steveincolorado

I re-wrote the for statements although I thought that it was okay to declare variables earlier in the program and just place a ";" in the place of the the variable declaration in the for statement? I was unable to get the k variable to compile without first declaring it.

Originally Posted by WaltP

No. You enclose the code in tags. You could possiblly use the PREVIEW button to see if your post looks right...



Yes you should declare your variables earlier in the program. And yes you can just ";" if you know what you're doing. The first position is not a variable declaraction is a variable initialization, the first value the variable has thru the loop.

Also, formatting is of primary importance. Every time you use { indent 4 spaces. Just before you use every }, unindent.

Formatted properly, you code looks like:

Help with Code Tags

C++ Syntax (Toggle Plain Text)

#include <iostream>
#include <string>
using std::cin;
using std::string;
using std::cout;
using std::endl;
int main()
{
    int i;
    int j;
    int k;
 
    const char STAR ='*';
    k=2;                    // What does this statement do for you?
                            // What's the value the second time thru the I loop?
    for(i=0; i<7; i++)
    {
        for(j=0;j<k;j=j++)
        {
            cout << STAR;
        }
        {                   // Why are you starting a new block?
            for(k=0;k < 14; k= k+2)
            cout << endl;
        }
    }
    return 0;
} //end of main function

#include <iostream> #include <string> using std::cin; using std::string; using std::cout; using std::endl; int main() { int i; int j; int k; const char STAR ='*'; k=2; // What does this statement do for you? // What's the value the second time thru the I loop? for(i=0; i<7; i++) { for(j=0;j<k;j=j++) { cout << STAR; } { // Why are you starting a new block? for(k=0;k < 14; k= k+2) cout << endl; } } return 0; } //end of main function

Originally Posted by steveincolorado

WaltP it never occured to me at the time to preview my post but your absolutely correct and thank you for the pointer on initialization of the variable.

Originally Posted by steveincolorado

My thinking was that I since I needed to print six lines of star's that I would have the outer loop run six times, ...

Originally Posted by steveincolorado

then I needed an inner loop to run six times but increment by 2 such that I would have another loop run 2 times, then 4, then 6, then 8, 10 and finally 12 times so that my cout <<STAR; statement would be printed by the same number each time through so that I would have the following output:

** print 2 times
**** print 4 times
****** print 6 times
******** print 8 times
********** print 10 times
************ print 12 times

Originally Posted by WaltP

Hmmmm.... no comment


Good thought.


You just complexed it out of reason.

Let's think about this... (yeah, I know that's what we're doing... )
You have one outer loop that goes from 0 to 6
for(i=0; i<7; i++)
That's 7 lines... What's wrong here? That you can fix easily.

Now you want 6 lines of 2, 4, 6, 8... *s. Your loop goes 0, 1, 2, 3...
Is there a correlation between what you want and your loop?

Originally Posted by steveincolorado

Okay for your first question I should change the for statement to i<6

Yes now that you have pointed it out I see that there is a correlation between the two sets.

My outer loop is:
0, 1,2,3,4,5
the difference between that and what I need to print is
2,3,4,5,6,7
so the inner loop actually would appread to be the outer loop number +1 right?
so I could add 1 to i for the inner loop such as j=i+2; ?

Thank you