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Removing found chars from string

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Removing found chars from string

Nov 7th, 2006

Hello all

I want to be able to search a string and remove non a-z chars and also search for certain words and then remove them

ie. char string[25]="STEPHEN JOHNSON - LTD"

So i use isalpha to get rid of the non a-z string

i am left with STEPHENJOHNSONLTD

LTD is the word i want to remove

How do i go about this?

Any help is much appreciated.

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Re: Removing found chars from string

Nov 7th, 2006

If other strings are similar remove everything after the second space.

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Re: Removing found chars from string

Nov 7th, 2006

to get rid of non-alpha characters -- use a pointer to check each char using isalpha() macro. When non-alpha char found, call movemem() to shift all remaining characters lincluding the null terminator left one byte to cover up the non-alpha character.

After you get that working we cal talk about removing the word. Don't try to do all of it all at the same time or you will have trouble doing any of it.

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Re: Removing found chars from string

Nov 7th, 2006

I have managed to get my string from

"STEPHEN JOHNSON - LTD"

to

"STEPHENJOHNSONLTD"

No i need to remove LTD

Thanks

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Re: Removing found chars from string

Nov 7th, 2006

First form your string like "STEPHEN JOHNSON".

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
for (i=0; i<25; i++, string++)
{
   if (*string == '-' && i != 0)
   {
      *(string-1) = '\0';
 
   }
}
for (i=0; i<25; i++, string++)
{
   if (*string == '-' && i != 0)
   {
      *(string-1) = '\0';
      
   }
}

and then remove the space.

If you want to win, you must not loose (Alan Ford)

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Re: Removing found chars from string

Nov 7th, 2006

But this doesnt help me remove a word as such does it?

I need to remove the word LTD from string

STEPHENJOHNSONLTD

Thanks

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Re: Removing found chars from string

Nov 7th, 2006

•

Originally Posted by andor

First form your string like "STEPHEN JOHNSON".
Help with Code Tags

c Syntax (Toggle Plain Text)
for (i=0; i<25; i++, string++)
{
   if (*string == '-' && i != 0)
   {
      *(string-1) = '\0';
 
   }
}
for (i=0; i<25; i++, string++) { if (*string == '-' && i != 0) { *(string-1) = '\0'; } }
and then remove the space.

why does the loop count to 25? What if the string does not contain 25 characters, or if it contains more than 25 characters. Hard-coding a number there is not a good idea.

>> if (*string == '-' && i != 0)
syntax error.

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Re: Removing found chars from string

Nov 7th, 2006

•

Originally Posted by sgriffiths

But this doesnt help me remove a word as such does it?

I need to remove the word LTD from string

STEPHENJOHNSONLTD

Thanks

use strstr() to find beginning of the word you want to remove, then use a pinter to shift everything left until either a space is found of end of string is found. Now lets see you post some code.

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Re: Removing found chars from string

Nov 7th, 2006

•

Originally Posted by Ancient Dragon

why does the loop count to 25? What if the string does not contain 25 characters, or if it contains more than 25 characters. Hard-coding a number there is not a good idea.

>> if (*string == '-' && i != 0)
syntax error.

Hm read the first post

•

Originally Posted by sgriffiths

ie. char string[25]="STEPHEN JOHNSON - LTD"

Whats the posibility that the string have more than 25 chars?

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <stdio.h>
 
int main()
{
   char p[25] = "STEPHEN JOHNSON - LTD";
   char *string = p;
   unsigned char i;
   printf("%s\n", p);
 
   for (i=0; i<25; i++, string++)
   {
      if (*string == '-' && i != 0)
      {
         *(string-1) = '\0';
         break; /* added this line */
      }
   }
   printf("%s\n", p);
   return 0;
}
#include <stdio.h>

int main()
{
   char p[25] = "STEPHEN JOHNSON - LTD";
   char *string = p;
   unsigned char i;
   printf("%s\n", p);
   
   for (i=0; i<25; i++, string++)
   {
      if (*string == '-' && i != 0)
      {
         *(string-1) = '\0';
         break; /* added this line */
      }
   }
   printf("%s\n", p);
   return 0;
}

Well I didn't posted the whole code.
Only thing is that I should break when '-' found.
EDIT: Simpler than using strlen

Last edited by andor; Nov 7th, 2006 at 9:05 am.

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Re: Removing found chars from string

#10

Nov 7th, 2006

•

Originally Posted by andor

Hm read the first post

Yes, I misread it. That is a good example of why the programmer should use pleanty of white space..

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Originally Posted by andor

whats the posibility that the string have more than 25 chars?

100 % when the string contains some other characters. Loops like that should be made more general to handle strings of any length. Hard-coding the string length is just sloppy programming.

Last edited by Ancient Dragon; Nov 7th, 2006 at 9:12 am.

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