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1/x1+...+1/x8=1/2

  #1  
Nov 29th, 2006
Hi
Help with the decision of the equation

1/x1 + 1/x2 + 1/x3 + 1/x4 + 1/x5 + 1/x6 + 1/x7 + 1/x8 = 1/2

x1 <= x2 <=x3 <=x4 <=x5 <=x6 <=x7 <=x8 (natural)

It is understandable, that 3 <=x1 <=16

what about x2, ... ,x8 ?

thanks
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Re: 1/x1+...+1/x8=1/2

  #2  
Nov 29th, 2006
Dp you mean solve for x?
If so, the easiest way to solve it is to multiply the whole equation by (x/2).
Please anyone, correct me if I am wrong. It is the best way for me to learn.
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Re: 1/x1+...+1/x8=1/2

  #3  
Dec 2nd, 2006
I'm not sure if it helps but you guys can use [tex] bbcode on here.
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