Assembly

inline assembly getting user input.(djgpp)

Please support our Assembly advertiser: Programming Forums - DaniWeb Sister Site

•

Join Date: Jul 2005

Posts: 18

Reputation: reyhan12 is an unknown quantity at this point

Solved Threads: 0

reyhan12

Offline

Newbie Poster

inline assembly getting user input.(djgpp)

Dec 2nd, 2006

How do i get user input in assembly? after getting the input, i'd like for the inputted value to be stored in a char array in c.
i'm new to assembly and i am having a hard time trying to figure this out.
i've tried a code like this and obviously it's wrong. lol

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
printf("Enter a 16 bit Hexadecimal number:");
__asm__ ("leal edx,%0;" 
	 "movl ah, 0ah;" 
	 "int 21h;"
	 : "=r" ( val )
	);
printf("Enter a 16 bit Hexadecimal number:");
__asm__ ("leal edx,%0;" 
	 "movl ah, 0ah;" 
	 "int 21h;"
	 : "=r" ( val )
	);

anyway, any help would be great. thanks!

•

Join Date: Aug 2005

Posts: 15,625

Reputation: Ancient Dragon has a reputation beyond repute

Solved Threads: 1496

Ancient Dragon Ancient Dragon is offline

Offline

Still Learning

Re: inline assembly getting user input.(djgpp)

Dec 2nd, 2006

you can't use interrupts in 32-bit protected-mode programs (e.g. windows or *nix programs). Easiest way is to call os C functions and let them deal with all the dirty stuff in protected mode. If you don't know how to do that there is another thread that will show you how to call ms-windows win32 api functions.

Last edited by Ancient Dragon; Dec 2nd, 2006 at 6:36 pm.

Don't PM me with questions -- you might get a nasty PM in response. If you have a question then post it in one of the forums.