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to secomd smallest number in array
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i want to find the second smallest number ib array but it is displaying second highest number
int max=0,second=0;
if(a[0]>a[1])
{
max=a[0];
second=a[1];
}
else
{
max=a[1];
second=a[0];
}
for( i=2;i<n;i++)
{
if(a[i]>=max)
{
second=max;
max=a[i];
}
else
if(a[i]>second)
second=a[i];
}
System.out.println("the second smallest nubmer is"+second);
int max=0,second=0;
if(a[0]>a[1])
{
max=a[0];
second=a[1];
}
else
{
max=a[1];
second=a[0];
}
for( i=2;i<n;i++)
{
if(a[i]>=max)
{
second=max;
max=a[i];
}
else
if(a[i]>second)
second=a[i];
}
System.out.println("the second smallest nubmer is"+second);
•
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Join Date: Dec 2004
Posts: 4,212
Reputation: 
Solved Threads: 489
I would suggest to sort the array first and then it is simple just reguest number on second possition. Also keep in mind that you may have first two number of same value so the second smallest should be on 3rd position(but that is just extra feature of your program)
Learn to see in another's calamity the ills which you should avoid.
Publilius Syrus
(~100 BC)
LJC - London Java Community, Graduate & Undergraduate Software Development Community, JAVAWUG (Java Web User Group), The London Android Group
Publilius Syrus
(~100 BC)
LJC - London Java Community, Graduate & Undergraduate Software Development Community, JAVAWUG (Java Web User Group), The London Android Group
Your instructor could also be extra devious and give you an array where all the indecies hold the same value. In which case the second smallest number would still be that value
•
•
Join Date: Feb 2007
Posts: 52
Reputation:
Solved Threads: 0
Junior Poster in Training
try this code.i have change few thing in u r code
int min=0,second=0;
if(a[0]<a[1])
{
min=a[0];
second=a[1];
}
else
{
min=a[1];
second=a[0];
}
for(int i=2;i<9;i++)
{
if(a[i]<=min)
{
second=min;
min=a[i];
}
else
{
if(a[i]<second)
second=a[i];
}
}
System.out.println("the second smallest nubmer is "+second);
int min=0,second=0;
if(a[0]<a[1])
{
min=a[0];
second=a[1];
}
else
{
min=a[1];
second=a[0];
}
for(int i=2;i<9;i++)
{
if(a[i]<=min)
{
second=min;
min=a[i];
}
else
{
if(a[i]<second)
second=a[i];
}
}
System.out.println("the second smallest nubmer is "+second);
•
•
•
•
Originally Posted by pavani2006 
i want to find the second smallest number ib array but it is displaying second highest number
int max=0,second=0;
if(a[0]>a[1])
{
max=a[0];
second=a[1];
}
else
{
max=a[1];
second=a[0];
}
for( i=2;i<n;i++)
{
if(a[i]>=max)
{
second=max;
max=a[i];
}
else
if(a[i]>second)
second=a[i];
}
System.out.println("the second smallest nubmer is"+second);
i m oblised for all member of daniweb.as helping me every time.this is best site for those who want to learn themself.
•
•
Join Date: Dec 2004
Posts: 4,212
Reputation:
Solved Threads: 489
Already I can see problem here, in both cases if/else statement will be useless if first two numbers will be some of largest. You are expecting smallest number to be on one of first two positions in array.
Consider following array and think about it again
Consider following array and think about it again
arr = {4, 5, 1, 3, 2} Last edited by peter_budo; Apr 8th, 2007 at 5:36 am.
Learn to see in another's calamity the ills which you should avoid.
Publilius Syrus
(~100 BC)
LJC - London Java Community, Graduate & Undergraduate Software Development Community, JAVAWUG (Java Web User Group), The London Android Group
Publilius Syrus
(~100 BC)
LJC - London Java Community, Graduate & Undergraduate Software Development Community, JAVAWUG (Java Web User Group), The London Android Group
•
•
Join Date: Feb 2007
Posts: 52
Reputation:
Solved Threads: 0
Junior Poster in Training
•
•
•
•
Originally Posted by peter_budo
Already I can see problem here, in both cases if/else statement will be useless if first two numbers will be some of largest. You are expecting smallest number to be on one of first two positions in array.
Consider following array and think about it again
arr = {4, 5, 1, 3, 2}
thanking u
i m oblised for all member of daniweb.as helping me every time.this is best site for those who want to learn themself.
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