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Join Date: Jul 2005
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Anyways, anyone have an answer for my question?
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Originally Posted by joshSCH 
Isn't that right? It better be.. I'm taking the Physics 2 "Mechanics w/ Calculus" AP test next month..
It's wrong actually. The correct answer is that you can't tell based on the data. It doesn't state where the combined masses come to a halt for example, nor the ground friction component acting on them. As such there's just one vector out of several you need to compute the entire energy distribution of the system before and after the collision (and that's when seeing it as a 2 dimensional solid body problem, it could be a 3 dimensional problem with other factors coming into play like the bodies dividing up their masses on collision causing multiple bodies to leave the scene afterwards, dispersing the energy).
As people are clearly allowed to attack me but I'm not allowed to defend myself, I no longer post to this site.
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Originally Posted by jwenting
It's wrong actually. The correct answer is that you can't tell based on the data. It doesn't state where the combined masses come to a halt for example, nor the ground friction component acting on them. As such there's just one vector out of several you need to compute the entire energy distribution of the system before and after the collision (and that's when seeing it as a 2 dimensional solid body problem, it could be a 3 dimensional problem with other factors coming into play like the bodies dividing up their masses on collision causing multiple bodies to leave the scene afterwards, dispersing the energy).
I think the objects are supposed to be assumed as point particles, rather than 3-dimensional objects. Also, other velocity variables (such as air resistance and static friction) should not be considered.
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Originally Posted by jwenting
It's wrong actually. The correct answer is that you can't tell based on the data. It doesn't state where the combined masses come to a halt for example, nor the ground friction component acting on them. As such there's just one vector out of several you need to compute the entire energy distribution of the system before and after the collision (and that's when seeing it as a 2 dimensional solid body problem, it could be a 3 dimensional problem with other factors coming into play like the bodies dividing up their masses on collision causing multiple bodies to leave the scene afterwards, dispersing the energy).
um yea.. based on the information given, the answer I gave was correct. Unless he wanted friction/air resistance and such considered in the problem he would have said so. He also mentions that this thread is not meant for really difficult problems.. So, perhaps you shouldn't be such a
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Originally Posted by joshSCH
Um.. actually it does. I was referring to the law of conservation of energy.. Kinetic energy is not conserved in inelastic collisions, therefore you know that the maximum kinetic energy is lost. However, The law of conservation of energy is true for the system. The energy is transferred from kinetic energy to different kinds of energy (sound, heat, etc.)
No, you do not know the maximum kinetic energy was lost from the fact that kinetic energy is not conserved in inelastic collisions; you know that the maximum possible amount of kinetic energy was lost because the problem statement tells you that the vehicles end up at rest.
You did not use the principle of conservation of energy anywhere in your solution to the problem; you used the law that momentum is conserved.
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can i make a chemistry question?
What mass of calcium carbonate (CaCO3) reacts completely with 25 cm3 of 2 mol/dm3 hydrocholric acid (HCL)?
CaC03 (s) + 2HCL (aq) -> CaCl2 (aq) + CO2 (g) + H2O (l)
For those of you who dont do chemistry heres a clue:
Its a 1:2 Ratio and n (moles) = m (mass) x Mr (Relative molecular mass)
This is simple really (i did it in school when i was 16 - all you need is a calculator and a periodic table)
What mass of calcium carbonate (CaCO3) reacts completely with 25 cm3 of 2 mol/dm3 hydrocholric acid (HCL)?
CaC03 (s) + 2HCL (aq) -> CaCl2 (aq) + CO2 (g) + H2O (l)
For those of you who dont do chemistry heres a clue:
Its a 1:2 Ratio and n (moles) = m (mass) x Mr (Relative molecular mass)
This is simple really (i did it in school when i was 16 - all you need is a calculator and a periodic table)
Last edited by jbennet : Apr 11th, 2007 at 8:34 pm.
TRY MY SUGGESTIONS AT YOUR OWN RISK!
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Originally Posted by Rashakil Fol
No, you do not know the maximum kinetic energy was lost from the fact that kinetic energy is not conserved in inelastic collisions; you know that the maximum possible amount of kinetic energy was lost because the problem statement tells you that the vehicles end up at rest.
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Originally Posted by Rashakil Fol
You did not use the principle of conservation of energy anywhere in your solution to the problem; you used the law that momentum is conserved.
All conservation laws are basically the same. The law of conservation of energy/mass is the exact same b/c energy and mass are related in the equation E=MC^2... The law of conservation of momentum involves torque, angular momentum,.. and basically the other laws..
Last edited by joshSCH : Apr 11th, 2007 at 8:35 pm.
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Originally Posted by jbennet
yay can i make a chemistry question?
Actually, no one has answered my question yet:
"The position vector of a particle of mass 3kg is given by r(vector)= 4i+3t^2j, where r is in meters and t is in seconds. Determine the angular momentum and torque acting on the particle about the origin."
But, It might be better to make a new thread titled "Chemistry Game" anyways...
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oh sorry i thaught you had finished ignore my question then
TRY MY SUGGESTIONS AT YOUR OWN RISK!
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