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Please help about USER INPUT

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Join Date: Apr 2007

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jenymaru08 jenymaru08 is offline

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Please help about USER INPUT

Apr 28th, 2007

Elow, I'm new member of this forum and also new in C++.I'm just start to learn it

I need help.....i want to write a program that will ask the use an integer number and output the word equivalent ofthe input(1000-3000)limit inclusive

example

input:1525
output: one thousand five hundred twenty-five

i will use a CONDITION STATEMENT but I;mconfuse with the CASE how willyou know if you will use CASE 1 Up to CASE 9

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
#include<iostream.h>
 
int main()
{
   int num,temp;
   cin>>num;
 
   if (num < 1000 || num > 3000)
     {
       cout<<"invalid";
   else 
      {
        temp=num/1000;
        num=num%1000;  
        switch(temp)
        {
           case 1:cout<<"one thousand";
#include<iostream.h>
 
int main()
{
   int num,temp;
   cin>>num;
   
   if (num < 1000 || num > 3000)
     {
       cout<<"invalid";
   else 
      {
        temp=num/1000;
        num=num%1000;  
        switch(temp)
        {
           case 1:cout<<"one thousand";

i dont know if I'm writing the right CODE, Please help i really dont have any idea about how will your ouput be in words

please help

thanks

Last edited by WolfPack; Apr 28th, 2007 at 10:03 am.

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Rashakil Fol Rashakil Fol is offline

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Re: Please help about USER INPUT

Apr 28th, 2007

This is certainly a non-trivial problem for somebody with your amount of experience.

Here's one tool I recommend using in the function, to make your time easier. Make an array or a vector which contains the numbers in string form, from "one" to "nineteen". I'm not sure what experience you have with C++, and whether you know how to use arrays or vectors, or about your knowledge of the string class, so I'll balk at a code example.

Make another array (or vector) that contains the names "twenty" through "ninety", too. With these, you won't need so many case statements. You won't need any, in fact.

Generally speaking, the strategy for this should be something like the following:

1. print out thousands part of the number
2. print out the hundreds part of the number
3. If the two-digit part is less than twenty, print out the name of the number. Otherwise, print out the name of the tens part, and then, if the units digit is nonzero, print out the hyphen and the units part name.

I don't understand your actual question, though. What don't you understand about switches and the case syntax?

Last edited by Rashakil Fol; Apr 28th, 2007 at 9:28 pm.

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Nichito

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Re: Please help about USER INPUT

Apr 28th, 2007

i will take my guess, and say you have low or no experience at all with c++... so... here's the deal... when you develop a switch, you write the code you want the program to run through in every case, and after every case, you write a break;, which will end the switch decision, and continue with the next part of the program...

Got it?

-->sometimes i wanna take my toaster in a bath<--

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Narue

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Re: Please help about USER INPUT

Apr 28th, 2007

>Got it?
Please. With that kind of explanation, even I wouldn't get it.

I'm here to prove you wrong.

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Nichito

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Re: Please help about USER INPUT

Apr 28th, 2007

lol... ok... here's more specific ok?

i've seen you've worked out part of the solution... so, here's what you might want to do...

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
case 1:
   cout<<"one thousand";
   break;
case 2:
   cout<<"two thousand";
   break;
case 3:
...
case 1:
   cout<<"one thousand";
   break;
case 2:
   cout<<"two thousand";
   break;
case 3:
...

by the way, i have a suggestion to make... why don't you better print only the quantity of thousands there are in the number, and, after the switch is finished you print "thousand"... (you should want to do the same thing with million, hundreds, etc...)

-->sometimes i wanna take my toaster in a bath<--