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Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

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Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
 #include <iostream.h>
char first[ 20 ];
char middle[ 20 ];
char last[ 20 ];
main()
{
    cout << "What is your name ScumBag? ";
    cin >> first >> "\n" >> middle >> "\n" >> last;
    return 0;
}
 #include <iostream.h>
char first[ 20 ];
char middle[ 20 ];
char last[ 20 ];
main()
{
    cout << "What is your name ScumBag? ";
    cin >> first >> "\n" >> middle >> "\n" >> last;
    return 0;
}

The aggrevation in codding, is that it does what I ask it to do, not what I want it to do.
The serenity in an idea, is though I was beaten to the punch, I was also assured to be on-track.

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

remove the "\n"s -- that is only for cout. Not allowed to have literals (text in quotes) on the cin line.

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

Wow, that was right up there on the bone headed's list then. Thanx.

The aggrevation in codding, is that it does what I ask it to do, not what I want it to do.
The serenity in an idea, is though I was beaten to the punch, I was also assured to be on-track.

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

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Originally Posted by Ancient Dragon

remove the "\n"s -- that is only for cout. Not allowed to have literals (text in quotes) on the cin line.

There is some syntax of cin that allowes us to ignore the \ns.. Isn't it?

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

>There is some syntax of cin that allowes us to ignore the \ns.. Isn't it?
You're probably thinking of the ws manipulator, but it discards all whitespace. If you want more control, you have to write your own manipulator:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
class scan {
public:
  scan ( const char *init ): fmt ( init ) {}
  friend istream& operator>> ( istream& in, const scan& s )
  {
    while ( *s.fmt != '\0' && in && in.peek() == *s.fmt ) {
      in.get();
      ++s.fmt;
    }
 
    if ( *s.fmt != '\0' )
      in.setstate ( ios::failbit );
 
    return in;
  }
private:
  mutable const char *fmt;
};
class scan {
public:
  scan ( const char *init ): fmt ( init ) {}
  friend istream& operator>> ( istream& in, const scan& s )
  {
    while ( *s.fmt != '\0' && in && in.peek() == *s.fmt ) {
      in.get();
      ++s.fmt;
    }

    if ( *s.fmt != '\0' )
      in.setstate ( ios::failbit );

    return in;
  }
private:
  mutable const char *fmt;
};

And of course you can write custom manipulators so that they're used in exactly the same way as standard manipulators. This is only slightly more awkward than what the OP had before:

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 C++ Syntax (Toggle Plain Text) 
cin>> first >> scan ( "\n" ) >> middle >> scan ( "\n" ) >> last;
cin>> first >> scan ( "\n" ) >> middle >> scan ( "\n" ) >> last;

Of course, that's effectively a no-op because most formatted input discards leading whitespace by default. That's why removing those strings altogether still works as expected.

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

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Originally Posted by NewKidWalking

Help with Code Tags

C++ Syntax (Toggle Plain Text)
 #include <iostream.h>
char first[ 20 ];
char middle[ 20 ];
char last[ 20 ];
main()
{
    cout << "What is your name ScumBag? ";
    cin >> first >> "\n" >> middle >> "\n" >> last;
    return 0;
}
#include <iostream.h> char first[ 20 ]; char middle[ 20 ]; char last[ 20 ]; main() { cout << "What is your name ScumBag? "; cin >> first >> "\n" >> middle >> "\n" >> last; return 0; }

You should get rid of the newline in your input for starters also you may want to tell the user to put in their first, middle, last names because the way you have it the name will just fill up the allocated space you've given and go to the next without ever really designating a first, middle or last name just the size of the characters.

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

also dont use <iostream.h> , use <iostream>

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Re: Hey, I got a very simple program here. Yet the compiler is disagreeing with me.

May 10th, 2007

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Originally Posted by NewKidWalking

Help with Code Tags

C++ Syntax (Toggle Plain Text)
 #include <iostream.h>
char first[ 20 ];
char middle[ 20 ];
char last[ 20 ];
main()
{
    cout << "What is your name ScumBag? ";
    cin >> first >> "\n" >> middle >> "\n" >> last;
    return 0;
}
#include <iostream.h> char first[ 20 ]; char middle[ 20 ]; char last[ 20 ]; main() { cout << "What is your name ScumBag? "; cin >> first >> "\n" >> middle >> "\n" >> last; return 0; }

hi...

the problem is, you cant put escape sequences in input functions like cin>>, it should be like this..

cin>>first;
cout<<"\n";
cin>>middle;
cout<<"\n";
cin>>last;

there..you should use cout<< for escape sequences...

good luck!!

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