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2D array allocation problem

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Join Date: Aug 2005

Posts: 148

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Micko

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Junior Poster

2D array allocation problem

Jun 6th, 2007

Hello guys,

It's been a while since I last time posted in this forum.
I have strange problem regarding matrix allocation. I was asked to write code that includes 2D array dynamic allocation. I write two version of matrix allocation.
Here is in my opinio relevant part of the code:

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <stdio.h>
#include <stdlib.h>
 
int main( void )
{
 
  int rows, cols;
  int i, j;
  /*int * mat1Blok;*/
  int ** mat1;
 
 
  printf("Enter number of rows: ");
  scanf("%d", &rows);
  printf("Enter number of columns: ");
  scanf("%d", &cols);
 
  /*memory allocation*/
 
   /* mat1Blok = malloc(rows * cols * sizeof(int));
	mat1 = malloc(rows * sizeof(int*));
	for (i = 0; i < rows; ++i)
	{
		mat1[i] = &mat1Blok[i * cols];
	}
	*/
 
  mat1 = malloc(cols * sizeof(int*));
  for(i = 0; i < cols; i++)
  {
		mat1[i] = malloc(rows * sizeof(int));
  }
 
	printf("\nEnter elements row by row:\n");
 
	for (i = 0; i < rows; i++)
	   for(j = 0; j < cols; j++)
	       scanf("%d",&mat1[i][j]);
    /*
    free (mat1);
    free (mat1Blok);
    */
 
    for (i = 0; i < cols; i++)
    {
        free (mat1[i]);
    }
    free (mat1);
    system("PAUSE");	
    return 0;
}
#include <stdio.h>
#include <stdlib.h>

int main( void )
{
  
  int rows, cols;
  int i, j;
  /*int * mat1Blok;*/
  int ** mat1;

  
  printf("Enter number of rows: ");
  scanf("%d", &rows);
  printf("Enter number of columns: ");
  scanf("%d", &cols);
  
  /*memory allocation*/

   /* mat1Blok = malloc(rows * cols * sizeof(int));
	mat1 = malloc(rows * sizeof(int*));
	for (i = 0; i < rows; ++i)
	{
		mat1[i] = &mat1Blok[i * cols];
	}
	*/
	
  mat1 = malloc(cols * sizeof(int*));
  for(i = 0; i < cols; i++)
  {
		mat1[i] = malloc(rows * sizeof(int));
  }
	
	printf("\nEnter elements row by row:\n");
	
	for (i = 0; i < rows; i++)
	   for(j = 0; j < cols; j++)
	       scanf("%d",&mat1[i][j]);
    /*
    free (mat1);
    free (mat1Blok);
    */
    
    for (i = 0; i < cols; i++)
    {
        free (mat1[i]);
    }
    free (mat1);
    system("PAUSE");	
    return 0;
}

I have tested both versions with Dev-Cpp on Windows platform and sent to my friend who discovered that if he uses version which is commented, everything is OK, but if he the use version as in the above code he gets segmentation fault when entering elements. He tested it in Linux. I don't have linux installed and i ask you to test this code and check if it will fail on linux machine. I don't see a reason for such behaviour and simply can't figure out what is wrong. He sad he got segmentation fault with rows = 3 and cols = 2.
Can you please check it?
Thanks

Last edited by Micko; Jun 6th, 2007 at 2:28 am.

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Join Date: Dec 2005

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Salem

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Re: 2D array allocation problem

Jun 6th, 2007

> mat1 = malloc(cols * sizeof(int*));
You've got the rows and cols mixed up in a couple of places.

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Join Date: Aug 2005

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Micko

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Junior Poster

Re: 2D array allocation problem

Jun 6th, 2007

•

Originally Posted by Salem

> mat1 = malloc(cols * sizeof(int*));
You've got the rows and cols mixed up in a couple of places.

Hmm, this is important part:

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
mat1 = malloc(cols * sizeof(int*));
  for(i = 0; i < cols; i++)
  {
		mat1[i] = malloc(rows * sizeof(int));
  }
mat1 = malloc(cols * sizeof(int*));
  for(i = 0; i < cols; i++)
  {
		mat1[i] = malloc(rows * sizeof(int));
  }

First I allocate array of pointerts to int. Every array member will point to new array of integers (columns). In every columns there are exactly "rows" elements.
Still don't understand, why this code works on windows machine and fails on linux.

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Narue

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Senior Bitch

Re: 2D array allocation problem

Jun 6th, 2007

You're mixing up the meaning of a row and a column. The following allocates using column major order (a[cols][rows]):

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 C Syntax (Toggle Plain Text) 
mat1 = malloc(cols * sizeof(int*));
for(i = 0; i < cols; i++)
{
  mat1[i] = malloc(rows * sizeof(int));
}
mat1 = malloc(cols * sizeof(int*));
for(i = 0; i < cols; i++)
{
  mat1[i] = malloc(rows * sizeof(int));
}

And this prints using row major order (a[rows][cols]):

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 C Syntax (Toggle Plain Text) 
for (i = 0; i < rows; i++)
  for(j = 0; j < cols; j++)
    scanf("%d",&mat1[i][j]);
for (i = 0; i < rows; i++)
  for(j = 0; j < cols; j++)
    scanf("%d",&mat1[i][j]);

Unless rows and cols have the same value, the two aren't interchangeable and you're accessing memory outside the bounds of the array you just allocated. Linux is giving you a segmentation fault.