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Join Date: Jul 2004
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how to reverse a numbers input by user Hello, my name is kerry and i just sign up .Well, my question is how do reverse a number input by user using recersive function.Thanks for the help.
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Join Date: Jul 2004
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U Means how to make a factorial program then mail me at saadkhulsai@yahoo.com
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Posting Whiz in Training
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Originally Posted by Kerry
Hello, my name is kerry and i just sign up .Well, my question is how do reverse a number input by user using recersive function.Thanks for the help.
You mean recursive funtion.The concept is quite simple.You take a number (to be reversed) and divide it by 10 and add the remainder to another number.As every loop goes by you multiply 10 to the other number and keep adding the remainders till you get 0.
Check this out
int n=12345,m=0;
cout<<"Orginal No:"<<n;
while(n>0)
{
m *= 10;
m += n%10;
n /= 10;
}
cout<<"\nRevesed No:"<<m; •
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Join Date: Jul 2004
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Newbie Poster
Hi,
Your problem can be solved in various way.This program is simplest(but layman process).Here i assumed that input number is in between integer range
(i.e.-32768 to 32767)
#include<stdio.h>
#incliude<conio.h>
void reverse(int num)
{
int i,div;
for(i=0;i<5;i++)
{
if(num>9)
{
printf("%d",div);
break;
}
div=num%10;
num*=/10;
printf("%d",div);
}
}
void main()
{
int num;
clrscr();
printf("\nEnter the number:");
scanf("%d",&num);
reverse(num);
getch();
}
N.B.
If you have any problem in C.Please send it to me with your id.I try my best to solve it.my id is rishi_works@yahoo.co.in
thanking you......
Rishiraj bayerd.
Your problem can be solved in various way.This program is simplest(but layman process).Here i assumed that input number is in between integer range
(i.e.-32768 to 32767)
#include<stdio.h>
#incliude<conio.h>
void reverse(int num)
{
int i,div;
for(i=0;i<5;i++)
{
if(num>9)
{
printf("%d",div);
break;
}
div=num%10;
num*=/10;
printf("%d",div);
}
}
void main()
{
int num;
clrscr();
printf("\nEnter the number:");
scanf("%d",&num);
reverse(num);
getch();
}
N.B.
If you have any problem in C.Please send it to me with your id.I try my best to solve it.my id is rishi_works@yahoo.co.in
thanking you......
Rishiraj bayerd.
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Join Date: Aug 2004
Location: india,AP
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Newbie Poster
reverse(int n)
{
long sum=0;int rem;
while(n>0)
{rem=n%10;
sum=sum*10+rem;
n=n/10;}
return sum;
main()
................................ hope u can do it from here.good luck.
{
long sum=0;int rem;
while(n>0)
{rem=n%10;
sum=sum*10+rem;
n=n/10;}
return sum;
main()
................................ hope u can do it from here.good luck.
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Join Date: Aug 2004
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Newbie Poster
the recursive code (function call itself ) will be as follow
#include <iostream>
#include <cstdlib>
int reverse_num (int n,int m) ;
using namespace std;
int main()
{
int n;
int m=0;
cout<<"enter number to reverse :";
cin>>n;
cout<<reverse_num(n,0)<<endl; //calling the function
system("pause") ;
return 0;
}
int reverse_num(int n,int m)
{
if(n==0)
return m; //base (exit condition)
m*=10;
m+=n%10;
return reverse_num(n/10,m); //recursive call
}
#include <iostream>
#include <cstdlib>
int reverse_num (int n,int m) ;
using namespace std;
int main()
{
int n;
int m=0;
cout<<"enter number to reverse :";
cin>>n;
cout<<reverse_num(n,0)<<endl; //calling the function
system("pause") ;
return 0;
}
int reverse_num(int n,int m)
{
if(n==0)
return m; //base (exit condition)
m*=10;
m+=n%10;
return reverse_num(n/10,m); //recursive call
}
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