Else If statement
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Else If statement Hello everyone, I just need help on this code. I can't debug it, I'm just new in Java and this is just my fifth assignment so I'm really having a hard time.
Here's my code:
the Error says that:
illegal start of type line 20
<identifier> expected line 20
Can anyone please tell me how to debug it? =/
Here's my code:
import java.io.*;
public class input
{
public static InputStreamReader Reader=new
InputStreamReader (System.in);
public static BufferedReader input=new
BufferedReader(Reader);
public static void main(String args[]);
String name;
int age;
double salary;
{
System.out.println("Enter name:");
name=input.readline();
System.out.println("Enter age:");
age=Integer.parseInt(input.readLine());
if(age<=18)
System.out.println("Too young!");
}
else if (age>=18);
{
System.out.println("You're ready to vote!");
}
}the Error says that:
illegal start of type line 20
<identifier> expected line 20
else if (age>=18);
Can anyone please tell me how to debug it? =/
Your braces and semicolons are out of place. Look through your if () else if () block and check them.
uhmmm.. I'm sorry, but I already tried to move the braces at the "else if" line. Still I can't let it run. =(
Look at the structure of your class and main() method and compare that with your other assignments which do run. Also, look at the brace structure of any if-else block. The problems should be reasily apparent to you.
This is about as basic as debugging can get and you need to spot the problems on your own to learn. I've already told you what the nature of the problem is, so all you have to do is look at those blocks.
This is about as basic as debugging can get and you need to spot the problems on your own to learn. I've already told you what the nature of the problem is, so all you have to do is look at those blocks.
arg.. a new error occured. >.< this is my only notes/guide for the if else statement. =(
The error says:
- unreported exception java.io.IOException; must be caught or
declared to be thrown line 12
- unreported exception java.io.IOException; must be caught or
declared to be thrown line 14
It seems like my teacher forgot something or I copied the code wrong. =(
import java.io.*;
public class input{
public static InputStreamReader Reader=new
InputStreamReader(System.in);
public static BufferedReader input=new
BufferedReader(Reader);
public static void main(String args[]){
String name;
int age;
{
System.out.println("Enter name:");
name=input.readLine();
System.out.println("Enter age:");
age=Integer.parseInt(input.readLine());
if (age<=17){
System.out.println("Too young!");
} else if(age>=18){
System.out.println("You're ready to vote!");
}
}
}
}The error says:
- unreported exception java.io.IOException; must be caught or
declared to be thrown line 12
name=input.readLine();
declared to be thrown line 14
age=Integer.parseInt(input.readLine());
It seems like my teacher forgot something or I copied the code wrong. =(
Last edited by rapperhuj : Sep 6th, 2007 at 9:48 pm.
I do not know what your teacher gave it to you and if you already covered Exceptions, but that what you get when you use BufferedReader getLine().
Check this tutorial and you should be able to figure it out what to do with it. Main difference between yours code and code in the tutorials is that you read from command line and tutorial do it from a file
Check this tutorial and you should be able to figure it out what to do with it. Main difference between yours code and code in the tutorials is that you read from command line and tutorial do it from a file
Learn to see in another's calamity the ills which you should avoid.
Publilius Syrus
(~100 BC)
LJC - London Java Community, JAVAWUG (Java Web User Group), The London Android Group
Publilius Syrus
(~100 BC)
LJC - London Java Community, JAVAWUG (Java Web User Group), The London Android Group
Using Scanner to read the input would be easier and you wouldn't have to mess with the ioexception.
http://java.sun.com/javase/6/docs/ap...l/Scanner.html
http://java.sun.com/javase/6/docs/ap...l/Scanner.html
or just add
throws IOException
underneath your main method declaration.
...
public static void main(String args[])
throws IOException {
String name;
...
that should work.
throws IOException
underneath your main method declaration.
...
public static void main(String args[])
throws IOException {
String name;
...
that should work.
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Originally Posted by thenava 
or just add
throws IOException
underneath your main method declaration.
...
public static void main(String args[])
throws IOException {
String name;
...
that should work.
No, main really should not throw exceptions. How do you intend to handle an exception that is thrown beyond the scope of your execution?
The catch block should be placed within main() and handle the exception gracefully.
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