array, unexpected output

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Join Date: Apr 2007

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sInFuL69er sInFuL69er is offline

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array, unexpected output

Sep 7th, 2007

Hi,
This is a segmant of my code that iam working on, for some reason its not giving out the expected output

which is 11010111. It gives me "elements: ☺ ☺ ☺ ☺ ☺ ☺" and its really bugging me cuz it looks right. Any help would be appriciated. Thanks

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unsigned char ipans[8],ipb[4]={1,0,1,1},epans[8];
int           ep[8] = {4,1,2,3,2,3,4,1};


int main()
{
    int x;
      
      printf("elements: ");
      for(x=0;x<8;x++)
      {
         epans[x] = ipb[ep[x]-1];
         printf("%c " ,epans[x]);
      }

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Join Date: Dec 2005

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Re: array, unexpected output

Sep 7th, 2007

Use %d
Not %c

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Join Date: Mar 2005

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TkTkorrovi TkTkorrovi is offline

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Re: array, unexpected output

Sep 7th, 2007

Yes, Salem is right, %c gives you a character with a corresponding code, not a number, 1 1 0 1 0 1 1 1 is exactly what your program outputs when you use %d. Also, when you initialize the arrays, you don't always have to provide the size, like in your program ipb [] = {1, 0, 1, 1} would work as well. One more thing, when you use the initialized arrays, it's often better to not use the array size anywhere, to avoid an unnecessary magic number. Like, in your array ep, the elements most likely cannot be 0, so, you can end this array with zero, and iterate until zero.

Last edited by TkTkorrovi : Sep 7th, 2007 at 1:04 pm.

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