Display all directories at links

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Views: 570 | Replies: 1

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Join Date: Dec 2005

Posts: 22

Reputation: magikman is an unknown quantity at this point

Rep Power: 3

Solved Threads: 0

magikman

Offline

Newbie Poster

Display all directories at links

Sep 26th, 2007

Hello,

I am trying to create a small php script that will display all but a few directories on my server as links. I have created the following code. I had it working when trying to ignore one directory, but now i would like to place the ignored directories within an array and ignore them that way. I am receiving the following error:

Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /WWW/it461.dvterry.com/index.php on line 31

Code:

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<?php
function listdirs($dir)
{
        static $alldirs = array();
        $dirs = glob($dir . '/*', GLOB_ONLYDIR);
        if (count($dirs) > 0)
        {
                foreach ($dirs as $d) $alldirs[] = $d;
        }

        foreach ($dirs as $dir) listdirs($dir);
        return $alldirs;
}
$ignoreArray = array("./test","./Homework_2");
?>

<html>
<head>
<title>
Main
</title>
</head>
<body>
<?php

        foreach(listdirs('.') as $dir)
        {
                if (!in_array($dir, $ignoreArray))
//              if ( $dir != "./Homework_2");
                {
                        echo "<a href="$dir">"$dir"</a><br />";
                }

        }
?>
</body>
</html>

Thanks!!