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Join Date: Aug 2007
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Newbie Poster
Hi All,
Small can some please let me know hpw to use logical OR in csh scripts, below is the code line which is not running and i don't know why it is entring in "if" statement, even though i'm inputing value "1",
set ans = $<
echo $ans
if ( $ans != 1 || $ans != "2" ) then
echo "Invalid option selected. Exixting from the from the script $0 ."
exit 0
endif
It goes in if clause and then exits from the script
Any suggestions pls .???
Small can some please let me know hpw to use logical OR in csh scripts, below is the code line which is not running and i don't know why it is entring in "if" statement, even though i'm inputing value "1",
set ans = $<
echo $ans
if ( $ans != 1 || $ans != "2" ) then
echo "Invalid option selected. Exixting from the from the script $0 ."
exit 0
endif
It goes in if clause and then exits from the script
Any suggestions pls .???
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Join Date: Feb 2006
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Because 1 != 2. If you want it to enter the if statement only when the input is not 1 and not 2, then you need to use the logical and (&&), not the logical (or).
If you wanted to enter the loop only if the answer is either 1 or 2, then you would use the logical or. i.e.
but, when you invert the == to !=, then you must also invert the or to an and, because every number is either not equal to one or not equal to two, one and two included.
If you wanted to enter the loop only if the answer is either 1 or 2, then you would use the logical or. i.e.
if ( $ans == 1 || $ans == 2 ) then
Java Programmer and Sun Systems Administrator
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
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Join Date: Aug 2007
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Newbie Poster
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Originally Posted by masijade 
Because 1 != 2. If you want it to enter the if statement only when the input is not 1 and not 2, then you need to use the logical and (&&), not the logical (or).
If you wanted to enter the loop only if the answer is either 1 or 2, then you would use the logical or. i.e.
but, when you invert the == to !=, then you must also invert the or to an and, because every number is either not equal to one or not equal to two, one and two included.if ( $ans == 1 || $ans == 2 ) then
Thanks mate Its working now !!!
It's an logical error from part ..
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