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Views: 964 | Replies: 7
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Join Date: Oct 2007
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Newbie Poster
reg OnlineExam Project hi
i am joshi. i got a problem in my project, ie i have declared 50 labels with a name q1,q2....q50 now i want to call these labels with a use of for loop..... but how
please help me....
i am joshi. i got a problem in my project, ie i have declared 50 labels with a name q1,q2....q50 now i want to call these labels with a use of for loop..... but how
please help me....
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Join Date: Apr 2007
Posts: 262
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Posting Whiz in Training
hii,
iam giving an example to display dynamically two labels.hope it is usefull.
if u have already have 5 labels in u r page but u want to display only 2 labels ,then this function is usefull
label1,label2 be u r label ids in the page
dim lbl as string
dim l as label
for 1=0 to 1
lbl="label"& convert.tostring(i)
l=page.findcontrol(lbl)
l.visible=true
next
iam giving an example to display dynamically two labels.hope it is usefull.
if u have already have 5 labels in u r page but u want to display only 2 labels ,then this function is usefull
label1,label2 be u r label ids in the page
dim lbl as string
dim l as label
for 1=0 to 1
lbl="label"& convert.tostring(i)
l=page.findcontrol(lbl)
l.visible=true
next
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Join Date: Oct 2007
Posts: 5
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Newbie Poster
hi
thq for your reply...
if i wrote l=page.findcontrol(lbl), i am getting an error that Error Cannot implicitly convert type 'System.Web.UI.Control' to 'System.Web.UI.WebControls.Label'. An explicit conversion exists (are you missing a cast?)
how can i slove this problem
please reply me.....
thq for your reply...
if i wrote l=page.findcontrol(lbl), i am getting an error that Error Cannot implicitly convert type 'System.Web.UI.Control' to 'System.Web.UI.WebControls.Label'. An explicit conversion exists (are you missing a cast?)
how can i slove this problem
please reply me.....
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Join Date: Apr 2007
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Posting Whiz in Training
hii,
did u declare l as label
dim l as label
thats the only reason i see for getting the error.the code i gave u was being used by me in my project .
did u declare l as label
dim l as label
thats the only reason i see for getting the error.the code i gave u was being used by me in my project .
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Join Date: Apr 2007
Posts: 262
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Posting Whiz in Training
hii,
i have figured it out.since u have declared starting from q1 ,the code i gave works from qo,so here is the correct code
Dim i As Integer
Dim lbl As Label
Dim b As String
For i = 0 To 1
b = "label" & Convert.ToString(i + 1)
lbl = Page.FindControl(b)
lbl.Visible = True
Next
i have figured it out.since u have declared starting from q1 ,the code i gave works from qo,so here is the correct code
Dim i As Integer
Dim lbl As Label
Dim b As String
For i = 0 To 1
b = "label" & Convert.ToString(i + 1)
lbl = Page.FindControl(b)
lbl.Visible = True
Next
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Join Date: Oct 2007
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Newbie Poster
hi
thanks for your reply ones again..
i have wrote same code but i am getting an error that "object reference is not set to an instance"
thanks for your reply ones again..
i have wrote same code but i am getting an error that "object reference is not set to an instance"
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Join Date: Sep 2007
Posts: 1,058
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Solved Threads: 61
You should not have to find the labels unless they are nested in another control like a datalist, grid, or repeater, etc. Try telling us what you want to do in this loop.
Oh, and the reason why his code isn't working for you is due to a few flaws. The below code is suited for you:
Oh, and the reason why his code isn't working for you is due to a few flaws. The below code is suited for you:
Public Function LoopingTheLbls() Dim i As Integer Dim lbl As Label Dim b As String For i = 0 To 49 b = "q" & Convert.ToString(i + 1) lbl = Page.FindControl(b) lbl.Text = "Help I am control " & (i + 1) next End Function
Last edited by SheSaidImaPregy : Oct 10th, 2007 at 2:51 am.
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