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Join Date: Oct 2007
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Newbie Poster
_ _ _ _ function2(_ _ _ _ _ _ _ _ _ _ _ );
main{
int n[]= {4, 5, 6};
int *kptr ;
kptr = function2( n ) ;
} Fill in the blanks and you get:
int *function2( int array[ ]); or
int *function2( int *ptr );
/* parameters names can be omitted */
main{
int n[]= {4, 5, 6};
int *kptr ;
kptr = function2( n ) ;
}Can you please tell me why its 'int *' in the function prototype, shudnt it be just 'void'? since its not returning anything? Or shudnt it just be 'int' excluding the '*', ?
Last edited by warpstar : Oct 25th, 2007 at 3:06 pm.
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How do you know it doesn't return anything? All you know (or at least have shown us), are the prototypes. I assume it assigns a value to the int pointer 'kptr' and because its type is an int star assignment from a function must return an int star.
Also, I assume this is an assignment? Hmm. Main returns an integer so 'int main()' with a 'return 0;' at the end of its scope is what you should be having. Was the 'blanked' code given by the teacher...
Also, I assume this is an assignment? Hmm. Main returns an integer so 'int main()' with a 'return 0;' at the end of its scope is what you should be having. Was the 'blanked' code given by the teacher...
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Thats a question taken from a sample midterm test, so that is what i assuming all you need to know to answer the question. I still dont really understand why the star is beside int in the function prototype. 
. Anyways thanks fr the reply.
. Anyways thanks fr the reply.•
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Originally Posted by twomers 
How do you know it doesn't return anything? All you know (or at least have shown us), are the prototypes. I assume it assigns a value to the int pointer 'kptr' and because its type is an int star assignment from a function must return an int star.
Also, I assume this is an assignment? Hmm. Main returns an integer so 'int main()' with a 'return 0;' at the end of its scope is what you should be having. Was the 'blanked' code given by the teacher...
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> since its not returning anything?
Well it needs to return something, because there is an assignment here.
kptr = function2( n ) ;
And it needs to return int* (not int), because that's the type of kptr.
Well it needs to return something, because there is an assignment here.
kptr = function2( n ) ;
And it needs to return int* (not int), because that's the type of kptr.
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Junior Poster in Training
>since its not returning anything?
I don't understand. It's clearly returning something because the code that calls the function uses the return value:
You can't use a function like that unless it returns something, and because kptr is declared as a pointer to int, it's a safe bet that function2 should return a pointer to int. The star means it's a pointer.
I don't understand. It's clearly returning something because the code that calls the function uses the return value:
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Originally Posted by warpstar
_ _ _ _ function2(_ _ _ _ _ _ _ _ _ _ _ ); main{ int n[]= {4, 5, 6}; int *kptr ; kptr = function2( n ) ; }
Fill in the blanks and you get:
int *function2( int array[ ]); or int *function2( int *ptr ); /* parameters names can be omitted */ main{ int n[]= {4, 5, 6}; int *kptr ; kptr = function2( n ) ; }
Can you please tell me why its 'int *' in the function prototype, shudnt it be just 'void'? since its not returning anything? Or shudnt it just be 'int' excluding the '*', ?
It isn't returning anything? Calling the function is accomplished by
kptr = function2( n ) ;isn't it? And doesn't it load the value into kptr which is an
int *? Got a cough? Go home tonight and eat a whole box of Ex-Lax. Tomorrow, you'll be afraid to cough.
-- Pearl Williams
-- Pearl Williams
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