Originally Posted by twomers

How do you know it doesn't return anything? All you know (or at least have shown us), are the prototypes. I assume it assigns a value to the int pointer 'kptr' and because its type is an int star assignment from a function must return an int star.

Also, I assume this is an assignment? Hmm. Main returns an integer so 'int main()' with a 'return 0;' at the end of its scope is what you should be having. Was the 'blanked' code given by the teacher...

Originally Posted by warpstar

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C++ Syntax (Toggle Plain Text)

 _ _ _ _ function2(_ _ _ _ _ _ _ _ _ _ _ );
main{
int n[]= {4, 5, 6};
int *kptr ;
kptr = function2( n ) ;
}

_ _ _ _ function2(_ _ _ _ _ _ _ _ _ _ _ ); main{ int n[]= {4, 5, 6}; int *kptr ; kptr = function2( n ) ; }

Fill in the blanks and you get:

Help with Code Tags

C++ Syntax (Toggle Plain Text)

int *function2( int array[ ]); or
int *function2( int *ptr );
/* parameters names can be omitted */
main{
int n[]= {4, 5, 6};
int *kptr ;
kptr = function2( n ) ;
}

int *function2( int array[ ]); or int *function2( int *ptr ); /* parameters names can be omitted */ main{ int n[]= {4, 5, 6}; int *kptr ; kptr = function2( n ) ; }

Can you please tell me why its 'int *' in the function prototype, shudnt it be just 'void'? since its not returning anything? Or shudnt it just be 'int' excluding the '*', ?