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Views: 1600 | Replies: 13 | Solved
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Join Date: Oct 2007
Posts: 11
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Newbie Poster
problem in printing Hexadecimal no's Need your help in this code too..
this is the program to convert any entered number into its hexadecimal equivalent but the problem is that same result is printed for any number...
this is the program to convert any entered number into its hexadecimal equivalent but the problem is that same result is printed for any number...
int main (void)
{
int n;
printf("Enter Number :");
scanf("%d", n);
printf("Hexadecimal Equivalent %x", n);
getch();
return 0;
}
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Join Date: Aug 2005
Location: near St Louis, Missouri, USA
Posts: 11,539
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>>but the problem is that same result is printed for any number
The scanf() line needs a pointer to n.
The scanf() line needs a pointer to n.
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Join Date: Sep 2004
Posts: 6,510
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>printf("Enter Number :");
You should call
You also need to include stdio.h. Your code presently exhibits undefined behavior.
>scanf("%d", n);
scanf takes a pointer to int so that it can store the value in your variable. Because n isn't already a pointer, you need to pass the address of n. You should also be checking the return value of scanf in case the user can't type or follow instructions.
>getch();
You need to include conio.h, but getchar is better because it's standard while getch is not.
Here's a better example:"
You should call
fflush ( stdout ) after this. The stream buffer is only guaranteed to be flushed when it's full (which you can't portably determine), when a newline is printed (which you aren't doing for this prompt), or when fflush is called. If stdout isn't flushed before the scanf call, your user may not see the prompt.You also need to include stdio.h. Your code presently exhibits undefined behavior.
>scanf("%d", n);
scanf takes a pointer to int so that it can store the value in your variable. Because n isn't already a pointer, you need to pass the address of n. You should also be checking the return value of scanf in case the user can't type or follow instructions.
>getch();
You need to include conio.h, but getchar is better because it's standard while getch is not.
Here's a better example:"
c Syntax (Toggle Plain Text)
I'm here to prove you wrong.
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Join Date: Dec 2005
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> scanf("%d", n);
Are you using gcc?
Have you considered
You forgot the &, which the above compiler/warning options would tell you.
Are you using gcc?
Have you considered
gcc -W -Wall prog.c
You forgot the &, which the above compiler/warning options would tell you.
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Join Date: Oct 2007
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Newbie Poster
Yes salem you r rite........
Im now wondering that how i forgot to put &
While compiling the following
compiler shows a warning..."code has no effect"
Im now wondering that how i forgot to put &
While compiling the following
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#include <stdio.h>
int main ( void )
{
int n;
printf ( "Enter Number: " );
fflush ( stdout );
if ( scanf ( "%d", &n ) == 1 )
printf ( "Hexadecimal Equivalent %x\n", n );
while ( getchar() != '\n' )
;
getchar();
return 0;
}
compiler shows a warning..."code has no effect"
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Join Date: Sep 2004
Posts: 6,510
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>compiler shows a warning..."code has no effect"
What line and what compiler?
What line and what compiler?
I'm here to prove you wrong.
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Join Date: Oct 2007
Posts: 11
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Newbie Poster
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getchar();
Borland C++
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Join Date: Sep 2004
Posts: 6,510
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>Borland C++
That makes sense. Borland likes to complain about unused results. You can safely ignore the warning (because getchar really does something here), or you can cast the result to void to silence the warning:
That makes sense. Borland likes to complain about unused results. You can safely ignore the warning (because getchar really does something here), or you can cast the result to void to silence the warning:
(void)getchar();
I'm here to prove you wrong.
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