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Extract the file name from the full file path.

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Join Date: Sep 2007

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eranga262154 eranga262154 is offline

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Re: Extract the file name from the full file path.

#11

Nov 9th, 2007

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Originally Posted by Salem

> if(ss.ReverseFind('\\')== 8) What does this return if there is no \\ ?

That what I'm really worried. That number is not fix always. It means, \\ can be missing in such instances.

I've try something like this also,

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CString aa = fileName.Right(fileName.GetLength() - (fileName.ReverseFind('\\') + 1));
CString aa = fileName.Right(fileName.GetLength() - (fileName.ReverseFind('\\') + 1));

Actually it gives the file path. Then use ReverseFind() again and find the '.', use a Left() to get the name only.

As you say, if the extension is missing this wont work.

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Salem

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Re: Extract the file name from the full file path.

#12

Nov 9th, 2007

Like I said, read the manual and find out what is returned when there is nothing to find, and use the appropriate if / else constructs to deal with it.

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hINTModuleState hINTModuleState is offline

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Using std::string, the solution would be :

-1

#13

Oct 26th, 2009

std::wstring PathToFileName(std::wstring strPath)
{
size_t found1 = strPath.rfind(L'\\');
size_t found2 = strPath.rfind(L'/');

size_t found = (found1!=std::wstring::npos) ? ( (found2!=std::wstring::npos) ? max(found1,found2) : found1 ) : found2;

std::wstring result = strPath.substr(found+1, strPath.length() - found-5);

return result;
}