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random numbers, and 2 dimensional array

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anga08628

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random numbers, and 2 dimensional array

Nov 9th, 2007

Define a 5 x10 2-dimensional array of integers (5 rows of 10 columns), randomly generate 50 numbers between 1 and 100, assign them to the array elements and display all the numbers on 5 lines of 10 integers each.

 Help with Code Tags 
 cpp Syntax (Toggle Plain Text) 
#include <iostream>
#include <ctime>    // For time()
#include <cstdlib>  // For srand() and rand()
 
 
using namespace std;
int main()
{
const int row=5;
const int column=10;
/*int rnum;*/
double table[row][column]; 
 
	/*srand(time(0));  // Initialize random number generator.
    rnum = (rand() % 50) + 1;
	if (rnum>1 && rnum <100)*/
	for(int r=0; r<row; r++)
	{ for(int c=0; c<column;c++)
		{ cout << table[row][column];
		}
	}
 
 
 
 
		system("pause");
		return 0;
}
#include <iostream>
#include <ctime>    // For time()
#include <cstdlib>  // For srand() and rand()


using namespace std;
int main()
{
const int row=5;
const int column=10;
/*int rnum;*/
double table[row][column]; 
	
	/*srand(time(0));  // Initialize random number generator.
    rnum = (rand() % 50) + 1;
	if (rnum>1 && rnum <100)*/
	for(int r=0; r<row; r++)
	{ for(int c=0; c<column;c++)
		{ cout << table[row][column];
		}
	}




		system("pause");
		return 0;
}

how would i apply the random part of this problem to the code?

Last edited by WaltP; Nov 9th, 2007 at 3:14 am. Reason: Added CODE tags -- you actually typed right over how to use them when you entered this post... And removed COLOR tags

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Re: random numbers, and 2 dimensional array

Nov 9th, 2007

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
cout << table[row][column];
cout << table[row][column];

Are you sure this is what you want to be doing?
In regard to implementing the random integers, you can just assign them as you print that particular cell. So add something before the above code.

On a minor note, why are you creating an array of doubles?

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Re: random numbers, and 2 dimensional array

Nov 9th, 2007

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
   rnum = (rand() % 50) + 1;
   if (rnum>1 && rnum <100)
   rnum = (rand() % 50) + 1;
   if (rnum>1 && rnum <100)

this is not doing quite what you want. rnum will be in the range 1-50. Your if condition will fail on value 1, which should be legitimate.

You're on the right track to get your 1-100 range, and you don't need the if statement.

You need to place the rand( ) statement inside the innermost loop, assigning that value to an array element.

If you choose to do the assignments and display in the same loops, you will also need to add some spacing between the outputs, and output a newline at the after the inner loop completes.

Val

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anga08628

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Re: random numbers, and 2 dimensional array

Nov 13th, 2007

what do you mean? i need to place the rand( ) statement inside the innermost loop, assigning that value to an array element.

how would i do that?

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maxmaxwell maxmaxwell is offline

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Re: random numbers, and 2 dimensional array

Nov 13th, 2007

You know how to populate a two dimensional array with an iteration(for, while etc.)statement right?
Do it the same way, except set the values equal to random numbers instead.

Last edited by maxmaxwell; Nov 13th, 2007 at 11:59 pm.

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Re: random numbers, and 2 dimensional array

Nov 16th, 2007

okay so the second part of this assingment is: Using a sort routine of your choice, sort the numbers in each of the rows of the array and display the sorted numbers again on 5 lines of 10 numbers each

i have no idea how to do this...in a 2d array. please help!

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Re: random numbers, and 2 dimensional array

Nov 16th, 2007

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Originally Posted by anga08628

okay so the second part of this assingment is: Using a sort routine of your choice, sort the numbers in each of the rows of the array and display the sorted numbers again on 5 lines of 10 numbers each

i have no idea how to do this...in a 2d array. please help!

You can't do this part until you get the first part done. Did you? If so, we can't see the code...

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Re: random numbers, and 2 dimensional array

Nov 17th, 2007

yes i did.
it this:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <ctime> // For time()
#include <cstdlib>  // For srand() and rand() 
#include <iomanip>
using namespace std;
 int table[5][10];
void sortarray (int[], int);
void showarray (int[], int);
 
int main()
{
	const int row=5;
	const int column=10;
	int table[row][column];
	int rnum;
	int t[row];
 
	srand(time(0));  // Initialize random number generator. 
	rnum = (rand() % 100) + 1;	
 
 
 
	for(int r=0; r<row; r++)//row	
	{ for(int c=0; c<column; c++)
	table [r][c] = (rand()%100) + 1;
	}
 
	for(int r=0; r<row; r++)//row	
	{ for(int c=0; c<column; c++) //column
 
	{ 
		cout << setw(5) << table[r][c] << ' '; //display table
 
	}
		cout << endl;
	}   
 
 
sortarray (t, row);
 
	cout << "your new sorted table is:  ";
	 showarray ( t, row);
 
 
 
 
	system("pause");		
	return 0;
 
}
 
 
 
void sortarrray(int t[], int elems)
{
	int temp;
	bool swap;
 
	do
	{
		swap=false;
		for (int count=0; count < (elems-1); count++)
		{
			if (t[count] > t[count +1])
			{ 
				 temp = t[count];
				t[count]=t[count +1];
				t[count +1]= temp;
				swap=true;
			}
		}
	}while (swap);
}
 
 
 
 
 
void showarray (int t[], int elems)
{
	for (int count=0; count < elems; count++)
		cout << t[count] << " ";
	cout << endl;
}
#include <iostream>
#include <ctime> // For time()
#include <cstdlib>  // For srand() and rand() 
#include <iomanip>
using namespace std;
 int table[5][10];
void sortarray (int[], int);
void showarray (int[], int);

int main()
{
	const int row=5;
	const int column=10;
	int table[row][column];
	int rnum;
	int t[row];
	
	srand(time(0));  // Initialize random number generator. 
	rnum = (rand() % 100) + 1;	
	


	for(int r=0; r<row; r++)//row	
	{ for(int c=0; c<column; c++)
	table [r][c] = (rand()%100) + 1;
	}
	
	for(int r=0; r<row; r++)//row	
	{ for(int c=0; c<column; c++) //column
	 
	{ 
		cout << setw(5) << table[r][c] << ' '; //display table
		 
	}
		cout << endl;
	}   


sortarray (t, row);

	cout << "your new sorted table is:  ";
	 showarray ( t, row);


	
	
	system("pause");		
	return 0;

}



void sortarrray(int t[], int elems)
{
	int temp;
	bool swap;

	do
	{
		swap=false;
		for (int count=0; count < (elems-1); count++)
		{
			if (t[count] > t[count +1])
			{ 
				 temp = t[count];
				t[count]=t[count +1];
				t[count +1]= temp;
				swap=true;
			}
		}
	}while (swap);
}





void showarray (int t[], int elems)
{
	for (int count=0; count < elems; count++)
		cout << t[count] << " ";
	cout << endl;
}

i tried doing the second part, but i didnt succeed. it also asks me to do a binary search...would it change if its a 2d array?

Last edited by cscgal; Nov 17th, 2007 at 3:31 pm. Reason: Added [code] tags.

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Re: random numbers, and 2 dimensional array

Nov 17th, 2007

you need to change the sort function to sort one column of a two-dimensional array

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
void sortarrray(int t[][10], int NumRows, int ColToSort)
{
   // sort code here
}
void sortarrray(int t[][10], int NumRows, int ColToSort)
{
   // sort code here
}

>>it also asks me to do a binary search...would it change if its a 2d array?
Very similar to the way you would sort it. Start out using the normal binary search algorithm for a one-dimensional array then expand it to use a 2-dimensional array that searches only one of the columns.

Last edited by Ancient Dragon; Nov 17th, 2007 at 6:19 pm.

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vmanes

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Re: random numbers, and 2 dimensional array

#10

Nov 17th, 2007

You have a sort function that will sort a 1D array, it looks to be correct.

In order to sort each row of the 2D array, pass each row to this function.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
int i;
for( i = 0; i < 5; i++ )
   sort_array( table[i], 10 );
int i;
for( i = 0; i < 5; i++ )
   sort_array( table[i], 10 );

Using just one index with a 2D array is the essentially accessing just that row, treating it as a 1D array.

Of course, you cannot do this with columns. That's a problem for another day.

Val