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C program to calculate number of days between 2 dates using structure of pointers....
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C program to calculate number of days between 2 dates using structure of pointers....
0
#1 Nov 14th, 2007
/*This program is going infinite.PLS help*/
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c,d,e,f,flag=0;
printf("Enter first date");
scanf("%d%d%d",&a,&b,&c);
printf("Enter second date");
scanf("%d%d%d",&d,&e,&f);
const int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
while(c!=f||b!=e||a!=d)
{
a++;
if((b==4)||(b==6)||(b==9)||(b==11))
f=30;
else if(b==2)
{
if(d%4==0)
f=29;
else
f=28;
}
else
f=31;
if(a>f)
{
b++;
a=1;
}
if(b==13)
{
c++;
b=1;
}
flag++;
}
printf("%d",flag);
getch();
}
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c,d,e,f,flag=0;
printf("Enter first date");
scanf("%d%d%d",&a,&b,&c);
printf("Enter second date");
scanf("%d%d%d",&d,&e,&f);
const int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
while(c!=f||b!=e||a!=d)
{
a++;
if((b==4)||(b==6)||(b==9)||(b==11))
f=30;
else if(b==2)
{
if(d%4==0)
f=29;
else
f=28;
}
else
f=31;
if(a>f)
{
b++;
a=1;
}
if(b==13)
{
c++;
b=1;
}
flag++;
}
printf("%d",flag);
getch();
}
Re: C program to calculate number of days between 2 dates using structure of pointers....
0
#2 Nov 14th, 2007
First of all: please use codetags. It makes your code easier to read:
I've replaced getch with getchar. void main with int main and removed conio. This makes your code standard for all compilers.
You might also want to use some usefull names for your vars. A,b,c, etc is not very practical.
Now for your problem:
What happens if a > d ? -> It becomes a while(1) loop. And that's just 1 problem of the many. What is this code supposed to do?
Niek
c Syntax (Toggle Plain Text)
I've replaced getch with getchar. void main with int main and removed conio. This makes your code standard for all compilers.
You might also want to use some usefull names for your vars. A,b,c, etc is not very practical.
Now for your problem:
What happens if a > d ? -> It becomes a while(1) loop. And that's just 1 problem of the many. What is this code supposed to do?
Niek
Last edited by niek_e; Nov 14th, 2007 at 6:07 am.
Re: C program to calculate number of days between 2 dates using structure of pointers....
0
#3 Nov 14th, 2007
Suppose a>d.
But the problem is while loop is infinite even if a<d
But the problem is while loop is infinite even if a<d
Re: C program to calculate number of days between 2 dates using structure of pointers....
0
#4 Nov 14th, 2007
•
•
•
•
Originally Posted by Myself 
What is this code supposed to do?
Niek
Re: C program to calculate number of days between 2 dates using structure of pointers....
0
#5 Nov 14th, 2007
hey i also solved in he same manner
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c,d,e,f,flag=0;
printf("Enter first date");
scanf("%d%d%d",&a,&b,&c);
printf("Enter second date");
scanf("%d%d%d",&d,&e,&f);
const int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
while(c!=f||b!=e||a!=d)
{
a++;
if((b==4)||(b==6)||(b==9)||(b==11))
f=30;
else if(b==2)
{
if(d%4==0)
f=29;
else
f=28;
}
else
f=31;
if(a>f)
{
b++;
a=1;
}
if(b==13)
{
c++;
b=1;
}
flag++;
}
printf("%d",flag);
getch();
}
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c,d,e,f,flag=0;
printf("Enter first date");
scanf("%d%d%d",&a,&b,&c);
printf("Enter second date");
scanf("%d%d%d",&d,&e,&f);
const int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
while(c!=f||b!=e||a!=d)
{
a++;
if((b==4)||(b==6)||(b==9)||(b==11))
f=30;
else if(b==2)
{
if(d%4==0)
f=29;
else
f=28;
}
else
f=31;
if(a>f)
{
b++;
a=1;
}
if(b==13)
{
c++;
b=1;
}
flag++;
}
printf("%d",flag);
getch();
}
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