Originally Posted by rpk5000

See that's just a rude comment. I of course actually read the policies, and am well aware that it would not make sense to just give me the answer. Maybe you should take time to consider that not all people on the site are as ignorant of the rules as some. Notice the part where I'm taking AP Comp Sci? Anyone in even the basic Java course could make a good stab at this problem. What I wanted was help understanding what he wanted me to do and what he was talking about in the second sentence.

Here's code to do it using an array of integers.

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Java Syntax (Toggle Plain Text)

Tester
case 3:
            System.out.println("Please Input a binary number");
            String ys;     
            ys=sc.next();      
            int [] binary = new int [ys.length()];
            for (int i = 0; i < binary.length; i++) {
              binary[i] = (int)ys.charAt(i)-(int)'0';
            }
            System.out.println("The number in base 10 is " + (mp.binToInt(binary)));
            break;
 
 
 
Method
  //pre: Given a binary number
//post Returns the decimal equivelent of the number as an integer
  public Integer binToInt(int[] binary) {
    int decimal = 0;
    for (int i = binary.length - 1; i > -1; i--) {
      decimal += Math.pow(2, (binary.length - i - 1)) * binary[i];
    }
    return decimal;
  }

Tester case 3: System.out.println("Please Input a binary number"); String ys; ys=sc.next(); int [] binary = new int [ys.length()]; for (int i = 0; i < binary.length; i++) { binary[i] = (int)ys.charAt(i)-(int)'0'; } System.out.println("The number in base 10 is " + (mp.binToInt(binary))); break; Method //pre: Given a binary number //post Returns the decimal equivelent of the number as an integer public Integer binToInt(int[] binary) { int decimal = 0; for (int i = binary.length - 1; i > -1; i--) { decimal += Math.pow(2, (binary.length - i - 1)) * binary[i]; } return decimal; }