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array problem
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hello to all.. i got a machine problem which is finding how many times the inputted number occured.. hows thar?
inputted number
bufferedReader)
Enter number: 22
Enter number: 23
Enter number: 32
Enter number: 32
Enter number: 23
Number to be search: 2
Occurence : 6
i cant get it..
pls help me tnx..
inputted number
bufferedReader)Enter number: 22
Enter number: 23
Enter number: 32
Enter number: 32
Enter number: 23
Number to be search: 2
Occurence : 6
i cant get it..
pls help me tnx..
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Join Date: May 2007
Posts: 4,515
Reputation: 
Solved Threads: 523
Post the code that you do have and we can take a look at it.
wah,,, my only prob here is i dont know how to read the inputted value and store it to become an array..
is this correct? bufferedreader to array? this is the code...
for(int a=0;a<5;a++)
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter Number : ");
str=br.readLine();
value[a]=Integer.parseInt(str);
}
is this correct? bufferedreader to array? this is the code...
for(int a=0;a<5;a++)
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter Number : ");
str=br.readLine();
value[a]=Integer.parseInt(str);
}
•
•
Join Date: May 2007
Posts: 4,515
Reputation:
Solved Threads: 523
Very close. Move the BufferedReader outside of your loop and put a try-catch block around the readLine() and parseInt() section.
BufferedReader data=new BufferedReader(new InputStreamReader(System.in));
System.out.print("Input number to be search: ");
try
{
ent=Integer.parseInt(data.readLine()); }
catch(IOException e)
{
}
is this correct? dunno how to store it as array..
System.out.print("Input number to be search: ");
try
{
ent=Integer.parseInt(data.readLine()); }
catch(IOException e)
{
}
is this correct? dunno how to store it as array..
peep.. my only problem now is counting the occurence...
enter number: 2
enter number: 222
enter number: 2
enter number: 222
enter number: 22
number to be searched is: 2
occurence: 10
but my occurence is showing only 2! it should be 10!
take a look at my code
enter number: 2
enter number: 222
enter number: 2
enter number: 222
enter number: 22
number to be searched is: 2
occurence: 10
but my occurence is showing only 2! it should be 10!
take a look at my code
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import java.io.*;
public class MP2
{
public static void main(String[] args) throws IOException
{
int value[]=new int[5];
int sear=0;
int d=0,c,a;
int high=0, low=0;
String str;
for(a=0;a<5;a++)
{
BufferedReader data=new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter Number : ");
str=data.readLine();
value[a]=Integer.parseInt(str);
}
BufferedReader data=new BufferedReader(new InputStreamReader(System.in));
System.out.print("Input number to be search: ");
str=data.readLine();
sear=Integer.parseInt(str);
for(c=0;c<5;c++)
{
if(sear==value[c])
d++;
}
System.out.print("Occurence is "+d);
}
}
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Join Date: Feb 2006
Posts: 2,467
Reputation:
Solved Threads: 267
because 2 != 222 or 22. If you really need to match each digit, then you need to parse each digit of the number as an Integer, rather than the entire String, of course. Try to work something in, in between the readLine and the parseInt and then, if it still doesn't work, post that modified code and clearly explain the problem, with all error/compiler messages (if any).
Java Programmer and Sun Systems Administrator
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
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