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Join Date: Nov 2007
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ok at runtime, if i enter "hello" in the console. the program should return "morse: .... . .-.. .-.. ---"currently it deosnt return anything. just ends.
Last edited by r5ingh : Nov 24th, 2007 at 12:30 pm.
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And this one...
void encode ( char ch );
char alph[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
/* morsecode is an array of pointers to char. It is initialized
* so that each element points to a string literal with
* the ascii representation of each char of the array alph[]
*/
char *morsecode[] =
{ /* an array of pointers to char */
".- " , "-..." , "-.-." , "-.." , "." , /* a-e */
"..-." , "--." , "...." , ".." , ".---" , /* f-j */
"-.-" , ".-.." , "--" , "-." , "---" , /* k-o */
".--." , "--.-" , ".-." , "..." , "-" , /* p-t */
"..-" , "...-" , ".--" , "-..-" , "-.--" , /* u-y */
"--.." , /* z */
};
int main ( void )
{
char text[100];
fputs ( "enter some text to convert to morse: ", stdout );
fflush ( stdout );
if ( fgets ( text, sizeof text, stdin ) != NULL )
{
char *newline = strchr ( text, '\n' ); /* search for newline character */
if ( newline != NULL )
{
*newline = '\0'; /* overwrite trailing newline */
}
printf ( "text = \"%s\"\n", text );
}
int j;
int foo = strlen(text);
for ( j = 0; j < foo; j++ )
{
encode ( toupper ( text[j] ) );
}
getchar();
getchar();
return 0;
}
void encode ( char ch )
{
size_t i, j;
for ( i = 0; i < 26; ++i )
{
if ( ch == alph[i] )
{
printf ( "%s", morsecode[i] );
break;
}
}
putchar ( '\n' );
} Last edited by iamthwee : Nov 24th, 2007 at 12:45 pm.
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r5ing:
A few things:
» Don't use scanf or it's non-standard variants for accepting user input. There are better ways of achieving it. Read this.
» The way you expose the interface doesn't seem to be right. Make encode() return a char array instead of nothing.
» Also since Morse code is case insensitive you might consider converting the user input to uppercase before applying encode function to it.
How do you expect this to work? You are assigning the string entered by the user to something which doesn't belong to you. You need to allocate enough memory. Something like
A few things:
» Don't use scanf or it's non-standard variants for accepting user input. There are better ways of achieving it. Read this.
» The way you expose the interface doesn't seem to be right. Make encode() return a char array instead of nothing.
» Also since Morse code is case insensitive you might consider converting the user input to uppercase before applying encode function to it.
c Syntax (Toggle Plain Text)
char ch[BUFSIZ] = { 0 }; Plus scanf requires you pass the starting address of the memory location. Since ch itself is a char array you just need to pass ch instead of &ch. "I don't accept change. I don't deserve to live."
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well?
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oooooooooooooooooooooooooooooooooooooooooooooooooooooooooo!
this works!!!
returns each char on a line. will chage this to return onto one line
this works!!!
returns each char on a line. will chage this to return onto one line
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S.O.S Thank you for the tips. i will read up on this. seems a bit advanced for me!! im a complete beginner!
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Mark this as being solved. (bottom rhs)
Next time use standard c and intent your code with spaces instead of tabs.
Next time use standard c and intent your code with spaces instead of tabs.
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I also need to be able to read input from a file. I have wrtten read methods for java, where you can define how data is parsed. but i do not know how to write the file read method in C. How will i parse the data into the program as a string?
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What have you got so far?
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C Syntax (Toggle Plain Text)
I need to get it to be something like this. so that i can meet the minimum requirements of the assessment.
i am thinking of useing a switch case statement, to call the encode function and i will write a separate function for the file read method.
iamthwee: i will mark it as solved if i do not need further assistance! Thanks for your help so far. I REALLY appreciate it!
Last edited by r5ingh : Nov 24th, 2007 at 12:52 pm.
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