comparing char with constant char

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Views: 1472 | Replies: 3 | Solved

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Join Date: Aug 2007

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toko

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comparing char with constant char

Nov 30th, 2007

okay i am trying to compare a char thats a constant with a char that a person has inputed however this is as far as i have gotten and its not working.

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#include <iostream>
using namespace std;

int main()
{
    char input[20];
    char correct [] = "Rudolf";
    cin >> request;
if (char request[] = char correct[])
    {
              cout << " correct";
    }
    else
    {
              cout << "incorrect";
     }
}

Any help is appreciated!!

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Join Date: Apr 2004

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Killer_Typo Killer_Typo is offline

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Re: comparing char with constant char

Nov 30th, 2007

Aside from the major syntax and naming issues:

thats because your array of 20 looks like

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Rudolf00000000000000
--------------------

// each 0 is actually a null character

where as the array you specify looks like this

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Rudolf
------

Last edited by Killer_Typo : Nov 30th, 2007 at 10:30 pm.

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Ancient Dragon Ancient Dragon is offline

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Re: comparing char with constant char

Nov 30th, 2007

try this: It does a case-sensitive comparison, such as "Rudolf" is not the same as "rudolf"

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#include <iostream>
using namespace std;

int main()
{
    char input[20];
    char correct [] = "Rudolf";
    cin >> input;
if (strcmp(input, correct) == 0)
    {
              cout << " correct";
    }
    else
    {
              cout << "incorrect";
     }
}

Last edited by Ancient Dragon : Nov 30th, 2007 at 11:02 pm.

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